在SQL中具有列的结果百分比

Question

我正在尝试获得一个结果，该结果将显示Uniuque“原因”，它们的数量以及它们占总数的百分比。到目前为止，我有

SELECT DISTINCT Reason, 
       COUNT(Reason) AS Number, 
       CAST(COUNT(Reason) AS float) / CAST(COUNT(*) AS float) AS percentage
FROM DeletedClients

但是，正如我发现的COUNT（*）和COUNT（原因）给出的结果一样。所以我的基本问题是，当我在查询中使用distinct时如何获得总行数？我正在使用SQL Server 2005

Answer 1

SELECT Reason, 
       COUNT(Reason) AS Number, 
       CAST(COUNT(Reason) AS float) / CAST(t.Total AS float) AS percentage
FROM DeletedClients,
     (SELECT COUNT(*) As Total FROM DeletedClients) t
GROUP BY Reason, Total