实时matplotlib图仍然在循环中不起作用

Nab*_*abs 8 python real-time matplotlib

我想创建一个实时图形绘图程序,它从串口输入.最初,我尝试了很多在网站上发布的代码,但都没有.所以,我决定通过集成我在网站上看到的代码片段来自己编写代码.但问题是图形将仅在程序结束时弹出,换句话说,在循环之外.在循环中,它没有显示任何内容,只是一个空白的画布.我仍然是python的新手.这是我的代码.

import matplotlib.pyplot as plt
import time
import random
from collections import deque
import numpy as np

# simulates input from serial port
def random_gen():
    while True:
        val = random.randint(1,10)
        yield val
        time.sleep(0.1)


a1 = deque([0]*100)
ax = plt.axes(xlim=(0, 20), ylim=(0, 10))
d = random_gen()

line, = plt.plot(a1)
plt.ion()
plt.ylim([0,10])
plt.show()

for i in range(0,20):
    a1.appendleft(next(d))
    datatoplot = a1.pop()
    line.set_ydata(a1) 
    plt.draw()
    print a1[0]
    i += 1
    time.sleep(0.1)
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另外,我使用Enthought Canopy学术许可证ver 1.1.0.

Dev*_*per 26

这是解决方案plt.pause(0.0001)在循环中添加如下:

import matplotlib.pyplot as plt
import time
import random
from collections import deque
import numpy as np

# simulates input from serial port
def random_gen():
    while True:
        val = random.randint(1,10)
        yield val
        time.sleep(0.1)


a1 = deque([0]*100)
ax = plt.axes(xlim=(0, 20), ylim=(0, 10))
d = random_gen()

line, = plt.plot(a1)
plt.ion()
plt.ylim([0,10])
plt.show()

for i in range(0,20):
    a1.appendleft(next(d))
    datatoplot = a1.pop()
    line.set_ydata(a1)
    plt.draw()
    print a1[0]
    i += 1
    time.sleep(0.1)
    plt.pause(0.0001)                       #add this it will be OK.
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  • 是的,这很有效.鉴于[这里](http://stackoverflow.com/questions/11874767/real-time-plotting-in-while-loop-with-matplotlib),没有任何答案对我有用. (2认同)