可以说我有一个名为test的表,如下所示:
ID DATE
1 '2013-01-26'
1 NULL
1 '2013-03-03'
2 '2013-02-23'
2 '2013-04-12'
2 '2013-05-02'
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我想从这张表中得到:
ID DATE
1 NULL
2 '2013-05-02'
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这是我的查询:
select ID, max(DATE)
from test
group by ID
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问题是MYSQL忽略NULL值并返回给我
ID DATE
1 '2013-03-03'
2 '2013-05-02'
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如果有NULL,我怎么能这样做,它需要MAX为NULL?
Sam*_*ley 23
试一试:
SELECT ID, case when MAX(DATE IS NULL) = 0 THEN max(DATE) END AS DATE
FROM test
GROUP BY ID;
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Null不是值或数字,它只是null.这就是你使用"where col1为null"而不是"col1 = null"的原因.解决方法是使用IFNULL并设置一个非常高的值.
select ID, max(IFNULL(DATE,'3000-01-01'))
from test
group by ID
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FYI在函数NULL中使用时会被忽略aggregation。
mysql> SELECT * FROM null_test;
+------+
| c |
+------+
| NULL |
| 1 |
| 2 |
| 3 |
+------+
4 rows in set (0.00 sec)
mysql> SELECT COUNT(c) FROM null_test;
+----------+
| COUNT(c) |
+----------+
| 3 | <= not 4 but 3
+----------+
1 row in set (0.00 sec)
mysql> SELECT COUNT(*) FROM null_test;
+----------+
| COUNT(*) |
+----------+
| 4 | <= in this case not 3 but 4
+----------+
1 row in set (0.00 sec)
mysql> SELECT AVG(c) FROM null_test;
+--------+
| AVG(c) |
+--------+
| 2.0000 | <= not (1+2+3) / 4 but (1+2+3) / 3
+--------+
1 row in set (0.00 sec)
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