Ton*_*ion 17 wpf select datagrid selecteditem
如何使用Datagrid.SelectedItem以编程方式选择行?
我首先要创建一个IEnumerable的DataGridRow对象和匹配的行传递给此SelectedItem属性或我该怎么办呢?
编辑:
TextBox.Text在选择行之前,我需要将第一列单元格的单元格内容与第一列匹配.
ser*_*nko 36
请检查以下代码是否适合您; 它遍历datagris第一列的单元格,并检查单元格内容是否等于textbox.text值并选择该行.
for (int i = 0; i < dataGrid.Items.Count; i++)
{
DataGridRow row = (DataGridRow)dataGrid.ItemContainerGenerator.ContainerFromIndex(i);
TextBlock cellContent = dataGrid.Columns[0].GetCellContent(row) as TextBlock;
if (cellContent != null && cellContent.Text.Equals(textBox1.Text))
{
object item = dataGrid.Items[i];
dataGrid.SelectedItem = item;
dataGrid.ScrollIntoView(item);
row.MoveFocus(new TraversalRequest(FocusNavigationDirection.Next));
break;
}
}
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希望这有帮助,问候
Moh*_*dil 22
您无需遍历DataGrid行,您可以通过更简单的解决方案实现目标.为了匹配您的行,您可以遍历绑定到DataGrid.ItemsSource属性的集合,然后以DataGrid.SelectedItem编程方式将此项目分配给您的属性,或者,DataGrid.SelectedItems如果您希望允许用户选择多行,则可以将其添加到集合中.请参阅以下代码:
<Window x:Class="ProgGridSelection.MainWindow"
xmlns="http://schemas.microsoft.com/winfx/2006/xaml/presentation"
xmlns:x="http://schemas.microsoft.com/winfx/2006/xaml"
Title="MainWindow" Height="350" Width="525" Loaded="OnWindowLoaded">
<StackPanel>
<DataGrid Name="empDataGrid" ItemsSource="{Binding}" Height="200"/>
<TextBox Name="empNameTextBox"/>
<Button Content="Click" Click="OnSelectionButtonClick" />
</StackPanel>
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public partial class MainWindow : Window
{
public class Employee
{
public string Code { get; set; }
public string Name { get; set; }
}
private ObservableCollection<Employee> _empCollection;
public MainWindow()
{
InitializeComponent();
}
private void OnWindowLoaded(object sender, RoutedEventArgs e)
{
// Generate test data
_empCollection =
new ObservableCollection<Employee>
{
new Employee {Code = "E001", Name = "Mohammed A. Fadil"},
new Employee {Code = "E013", Name = "Ahmed Yousif"},
new Employee {Code = "E431", Name = "Jasmin Kamal"},
};
/* Set the Window.DataContext, alternatively you can set your
* DataGrid DataContext property to the employees collection.
* on the other hand, you you have to bind your DataGrid
* DataContext property to the DataContext (see the XAML code)
*/
DataContext = _empCollection;
}
private void OnSelectionButtonClick(object sender, RoutedEventArgs e)
{
/* select the employee that his name matches the
* name on the TextBox
*/
var emp = (from i in _empCollection
where i.Name == empNameTextBox.Text.Trim()
select i).FirstOrDefault();
/* Now, to set the selected item on the DataGrid you just need
* assign the matched employee to your DataGrid SeletedItem
* property, alternatively you can add it to your DataGrid
* SelectedItems collection if you want to allow the user
* to select more than one row, e.g.:
* empDataGrid.SelectedItems.Add(emp);
*/
if (emp != null)
empDataGrid.SelectedItem = emp;
}
}
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小智 8
我搜索过类似问题的解决方案,也许我的方式会帮助你和任何面对它的人.
我 SelectedValuePath="id"在XAML DataGrid定义中使用,并且我只需要做的事就是设置DataGrid.SelectedValue为所需的值.
我知道这个解决方案有利有弊,但在具体情况下快速而简单.
最好的祝福
马尔钦
做你想做的事情比我更喜欢做的有点棘手,但那是因为你并没有直接将a绑定DataGrid到a DataTable.
当你绑定DataGrid.ItemsSource到a时DataTable,你真的将它绑定到默认值DataView,而不是绑定到表本身.这就是为什么,例如,DataGrid当您单击列标题时,您不必执行任何操作来创建排序行 - 该功能已被烘焙DataView,并且DataGrid知道如何访问它(通过IBindingList界面).
该DataView工具IEnumerable<DataRowView>(更多或更少),并DataGrid通过遍历该填充其项目.这意味着当你绑定DataGrid.ItemsSource到a时DataTable,它的SelectedItem属性将是a DataRowView,而不是a DataRow.
如果您了解所有这些,那么构建一个包装类非常简单,它允许您公开可以绑定的属性.有三个关键属性:
Table的DataTable,Row,类型的双向可绑定属性DataRowView,和SearchText,一个字符串属性,当它被设置时,将DataRowView在表的默认视图中找到第一个匹配项,设置Row属性并引发PropertyChanged.它看起来像这样:
public class DataTableWrapper : INotifyPropertyChanged
{
private DataRowView _Row;
private string _SearchText;
public DataTableWrapper()
{
// using a parameterless constructor lets you create it directly in XAML
DataTable t = new DataTable();
t.Columns.Add("id", typeof (int));
t.Columns.Add("text", typeof (string));
// let's acquire some sample data
t.Rows.Add(new object[] { 1, "Tower"});
t.Rows.Add(new object[] { 2, "Luxor" });
t.Rows.Add(new object[] { 3, "American" });
t.Rows.Add(new object[] { 4, "Festival" });
t.Rows.Add(new object[] { 5, "Worldwide" });
t.Rows.Add(new object[] { 6, "Continental" });
t.Rows.Add(new object[] { 7, "Imperial" });
Table = t;
}
// you should have this defined as a code snippet if you work with WPF
private void OnPropertyChanged(string propertyName)
{
PropertyChangedEventHandler h = PropertyChanged;
if (h != null)
{
h(this, new PropertyChangedEventArgs(propertyName));
}
}
public event PropertyChangedEventHandler PropertyChanged;
// SelectedItem gets bound to this two-way
public DataRowView Row
{
get { return _Row; }
set
{
if (_Row != value)
{
_Row = value;
OnPropertyChanged("Row");
}
}
}
// the search TextBox is bound two-way to this
public string SearchText
{
get { return _SearchText; }
set
{
if (_SearchText != value)
{
_SearchText = value;
Row = Table.DefaultView.OfType<DataRowView>()
.Where(x => x.Row.Field<string>("text").Contains(_SearchText))
.FirstOrDefault();
}
}
}
public DataTable Table { get; private set; }
}
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这是使用它的XAML:
<Window x:Class="DataGridSelectionDemo.MainWindow"
xmlns="http://schemas.microsoft.com/winfx/2006/xaml/presentation"
xmlns:x="http://schemas.microsoft.com/winfx/2006/xaml"
xmlns:dg="clr-namespace:Microsoft.Windows.Controls;assembly=WPFToolkit"
xmlns:DataGridSelectionDemo="clr-namespace:DataGridSelectionDemo"
Title="DataGrid selection demo"
Height="350"
Width="525">
<Window.DataContext>
<DataGridSelectionDemo:DataTableWrapper />
</Window.DataContext>
<DockPanel>
<Grid DockPanel.Dock="Top">
<Grid.ColumnDefinitions>
<ColumnDefinition Width="Auto" />
<ColumnDefinition Width="*" />
</Grid.ColumnDefinitions>
<Label>Text</Label>
<TextBox Grid.Column="1"
Text="{Binding SearchText, Mode=TwoWay}" />
</Grid>
<dg:DataGrid DockPanel.Dock="Top"
ItemsSource="{Binding Table}"
SelectedItem="{Binding Row, Mode=TwoWay}" />
</DockPanel>
</Window>
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