如何通过引用传递对象到构造函数

Question

我想通过引用将对象传递给Contructor,但是我遇到了问题,因为我不知道如何将它绑定到类的变量.

在这里,我发布了一些代码,错误上升了.

class ShortestPath{
    public:
        ShortestPath(Graph& graph): graph(graph){};[...]
    private:
        Graph *graph; 
};

在这种情况下,错误上升是:

cannot convert `Graph' to `Graph*' in initialization 

如果我写

ShortestPath(Graph& graph): *graph(graph){};[...]

错误是

expected identifier before '*' token 

当我调用构造函数时,我应该这样调用吗？最短路径(图表);

Answer 1

您必须以这种方式更改您的代码:

class ShortestPath{
public:
    ShortestPath(Graph& graph): graph(graph){};[...]
private:
    Graph &graph; 
}

要么:

 class ShortestPath{
public:
    ShortestPath(Graph& graph): graph(&graph){};[...]
private:
    Graph *graph; 
}