更新php函数

Question

有没有办法在执行每个mysqli_query函数后调用代码片段？在MySQL中有插入触发器之前和之后.我在PHP中寻找类似的东西.

在以下示例中,我需要在每次查询后自动记录所有警告(即不更改当前代码)

<?php
  $con = mysqli_connect('localhost', '', '', '');
  if (mysqli_connect_errno()) {
    print 'Failed to connect to MySQL: ' . mysqli_connect_error() . "\n";
    exit(1);
  }

  if (!mysqli_query($con, 'INSERT INTO dp4 (customer_id, first_name, last_name) ' .
                          'VALUES (NULL,"Chris","abc") ')) {
    print 'Failed to insert data: ' . mysqli_error($con) . "\n";
  }
  if (($warnings = mysqli_warning_count($con)) > 0) {
    if ($rs = mysqli_query($con, "SHOW WARNINGS")) {
        $row = mysqli_fetch_row($rs);
        printf("%s (%d): %s\n", $row[0], $row[1], $row[2]);
        mysqli_free_result($rs);
    }
  }
  mysqli_close($con);
?>

换句话说,if之后的代码(($ warnings应该以某种方式在它自己上运行,并将警告优先记录到文本文件中).

Answer 1

不是没有改变代码.您应该创建自己的查询函数来执行查询,记录它所需的内容,返回结果并使用它来代替mysqli_query().