如何以编程方式更改VBA项目的条件编译属性

Question

我目前正在开发一个VBA代码生成器/注入器,它通过使用VBA可扩展性将VBA功能添加到Excel工作簿.一切正常.

但是,注入的原始代码使用条件编译,引用一些全局条件编译参数:

有没有什么办法可以编程修改/添加VBA项目的条件编译参数？

我检查了VBProject的所有属性但找不到任何东西.

Answer 1

灵感来自这一做法,由SiddharthRout所示,我设法使用发现以下解决方案SendMessage和FindWindow:

Option Explicit

Private Declare Function FindWindow Lib "user32" Alias "FindWindowA" _
(ByVal lpClassName As String, ByVal lpWindowName As String) As Long

Private Declare Function FindWindowEx Lib "user32" Alias "FindWindowExA" _
(ByVal hWnd1 As Long, ByVal hWnd2 As Long, ByVal lpsz1 As String, _
ByVal lpsz2 As String) As Long

Private Declare Function GetWindowText Lib "user32" Alias "GetWindowTextA" _
(ByVal hwnd As Long, ByVal lpString As String, ByVal cch As Long) As Long

Private Declare Function GetWindowTextLength Lib "user32" Alias _
"GetWindowTextLengthA" (ByVal hwnd As Long) As Long

Private Declare Function SendMessage Lib "user32" Alias "SendMessageA" _
(ByVal hwnd As Long, ByVal wMsg As Long, ByVal wParam As Long, lParam As Any) As Long

Const WM_SETTEXT = &HC
Const BM_CLICK = &HF5


Public Sub subSetconditionalCompilationArguments()
    Dim strArgument As String
    Dim xlApp As Object
    Dim wbTarget As Object

    Dim lngHWnd As Long, lngHDialog As Long
    Dim lngHEdit As Long, lngHButton As Long

    strArgument = "PACKAGE_1 = 1"

    Set xlApp = CreateObject("Excel.Application")
    xlApp.Visible = False

    Set wbTarget = xlApp.Workbooks.Open("C:\Temp\Sample.xlsb")

    'Launch the VBA Project Properties Dialog
    xlApp.VBE.CommandBars(1).FindControl(ID:=2578, recursive:=True).Execute

    'Get the handle of the "VBAProject" Window
    lngHWnd = FindWindow("#32770", vbNullString)
    If lngHWnd = 0 Then
        MsgBox "VBAProject Property Window not found!"
        GoTo Finalize
    End If

    'Get the handle of the dialog
    lngHDialog = FindWindowEx(lngHWnd, ByVal 0&, "#32770", vbNullString)
    If lngHDialog = 0 Then
        MsgBox "VBAProject Property Window could not be accessed!"
        GoTo Finalize
    End If

    'Get the handle of the 5th edit box
    lngHEdit = fctLngGetHandle("Edit", lngHDialog, 5)
    If lngHEdit = 0 Then
        MsgBox "Conditional Compilation Arguments box could not be accessed!"
        GoTo Finalize
    End If

    'Enter new argument
    SendMessage lngHEdit, WM_SETTEXT, False, ByVal strArgument

    DoEvents

    'Get the handle of the second button box (=OK button)
    lngHButton = fctLngGetHandle("Button", lngHWnd)
    If lngHButton = 0 Then
        MsgBox "Could not find OK button!"
        GoTo Finalize
    End If

    'Click the OK Button
    SendMessage lngHButton, BM_CLICK, 0, vbNullString

Finalize:
    xlApp.Visible = True
    'Potentially save the file and close the app here
End Sub

Private Function fctLngGetHandle(strClass As String, lngHParent As Long, _
    Optional Nth As Integer = 1) As Long
    Dim lngHandle As Long
    Dim i As Integer

    lngHandle = FindWindowEx(lngHParent, ByVal 0&, strClass, vbNullString)
    If Nth = 1 Then GoTo Finalize

    For i = 2 To Nth
        lngHandle = FindWindowEx(lngHParent, lngHandle, strClass, vbNullString)
    Next
Finalize:
    fctLngGetHandle = lngHandle
End Function

Answer 2

对于Access 2000我用过:

Application.GetOption("Conditional Compilation Arguments")

得到的,

Application.SetOption("Conditional Compilation Arguments", "<arguments>")

用于设置.

就这样.

Answer 3

影响该对话框中任何内容的唯一方法是通过SendMessageAPI函数,或者可能Application.SendKeys.你最好在代码中声明常量,如下所示:

#Const PACKAGE_1 = 0

然后让您的代码修改CodeModule所有VBA组件:

Dim comp As VBComponent
For Each comp In ThisWorkbook.VBProject.VBComponents
    With comp.CodeModule
        Dim i As Long
        For i = 1 To .CountOfLines
            If Left$(.Lines(i, 1), 18) = "#Const PACKAGE_1 =" Then
                .ReplaceLine i, "#Const PACKAGE_1 = 1"
            End If
        Next i
    End With
Next comp