我有一些代码,我想用它来查找已排序文件中的重复项.(awk启发的)代码如下所示:
perl -wnla -e 'BEGIN {$previous = -1} $F[1] == $previous ? print $F[1] : $previous = $F[1]' ../VCF/FIN_20.vcf
Run Code Online (Sandbox Code Playgroud)
不幸的是它给了我一个错误:
Can't modify print in scalar assignment at -e line 1, at EOF
Execution of -e aborted due to compilation errors.
Run Code Online (Sandbox Code Playgroud)
我需要做些什么才能让它发挥作用?
PS.该文件看起来像
20 5282284 rs73594467
20 5282299 rs148317959
20 5282336 rs927106
Run Code Online (Sandbox Code Playgroud)
只需在最后一条指令中添加parens:
perl -wnla -e 'BEGIN {$previous = -1} $F[1] == $previous ? print $F[1] : ($previous = $F[1])'
# here ___^ ___^
Run Code Online (Sandbox Code Playgroud)
没有他们,就像:
($F[1] == $previous ? print $F[1] : $previous) = $F[1]
Run Code Online (Sandbox Code Playgroud)