我有这样的表:
表格1:
id | item_name | entered_by | modify_by
1 | banana | 2 | 1
2 | apple | 4 | 3
3 | orance | 1 | 1
4 | pineapple | 5 | 3
5 | grape | 6 | 1
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表2:
id | username
1 | admin
2 | jack
3 | danny
4 | dummy
5 | john
6 | peter
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查询可以正常工作,以选择enter_by或modify_by是否有值:
SELECT t1.id, t1.item_name,
t2enteredBy.username enteredBy,
t2modifyBy.username modifyBy
FROM table1 t1
JOIN table2 t2enteredBy ON t1.entered_by = t2enteredBy.id
JOIN table2 t2modifyBy ON t1.modify_by = t2modifyBy.id
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问题:如果modifiy_by或entered_by字段中的一个具有空值,则该行现在显示出来,如果它具有空值而不是完全隐藏该行,我需要它将其显示为" - ".
试试这个:
SELECT t1.id, t1.item_name,
COALESCE(t2enteredBy.username, '-') enteredBy,
COALESCE(t2modifyBy.username, '-') modifyBy
FROM table1 t1
LEFT JOIN table2 t2enteredBy ON t1.entered_by = t2enteredBy.id
LEFT JOIN table2 t2modifyBy ON t1.modify_by = t2modifyBy.id
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小提琴这里.
您需要left join使用null值返回这些行.然后,coalesce如果它们是,则确保它们被给定的字符串替换null.