Dev*_*Dev 8 mysql sql inverse-transform
我有这个查询,我想选择选择的反转.
SELECT Guide.id FROM Guide
INNER JOIN GuideAvailability ON Guide.id = GuideAvailability.guideId
WHERE GuideAvailability.startDate IN (1377946800)
GROUP BY GuideAvailability.guideId
HAVING COUNT(DISTINCT GuideAvailability.id) = 1
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有没有简单的方法来解决我的问题?
Cod*_*ver 16
只需使用此查询:
SELECT *
FROM Guide where id NOT IN (
SELECT Guide.id
FROM Guide
INNER JOIN GuideAvailability ON Guide.id = GuideAvailability.guideId
WHERE GuideAvailability.startDate IN (1377946800)
GROUP BY GuideAvailability.guideId
HAVING COUNT(DISTINCT GuideAvailability.id) = 1
)
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