CSRF cookie未设置django ...验证失败

Question

AoA我是Django的新手,我试图从POST获取数据,但是没有设置错误CSRF cookie,我尝试了很多通过谷歌在google和stackoverflow上找到解决方案,但是失败了

这是代码

views.py

    from django.http import HttpResponse
    from django.template.loader import get_template
    from django.template import Context
    from django.template import RequestContext
    from django.core.context_processors import csrf
    from django.shortcuts import render_to_response

def search_Post(request):
    if request.method == 'POST':
            c = {}
        c.update(csrf(request))
        # ... view code here
                return render_to_response("search.html", c)

def search_Page(request):
    name='Awais you have visited my website :P'
    t = get_template('search.html')
    html = t.render(Context({'name':name}))
    return HttpResponse(html)

HTML文件

<p>
          {{ name }}
            <form method="POST" action="/save/">
              {% csrf_token %}
              <textarea name="content" rows="20" cols="60">{{content}}</textarea><br>
              <input type="submit" value="Save Page"/>
            </form>
       <div>  Cant figure out any solution! :( </div>

 </p>

url.py

 url(r'^home/$', 'contacts.views.home_Page'),
 url(r'^save/$', 'contacts.views.search_Post'),
 url(r'^edit/$', 'contacts.views.edit_Page'),
 url(r'^search/$', 'contacts.views.search_Page'),

settings.py

TEMPLATE_CONTEXT_PROCESSORS = (
    'django.core.context_processors.csrf',
    'django.contrib.auth.context_processors.auth',
    'django.core.context_processors.debug',
    'django.core.context_processors.i18n',
    'django.core.context_processors.media',
    'django.core.context_processors.static',
    'django.core.context_processors.request',
    'django.contrib.messages.context_processors.messages'
)

MIDDLEWARE_CLASSES = (
    'django.middleware.common.CommonMiddleware',
    'django.contrib.sessions.middleware.SessionMiddleware',
    'django.middleware.csrf.CsrfViewMiddleware',
    'django.contrib.auth.middleware.AuthenticationMiddleware',
    'django.contrib.messages.middleware.MessageMiddleware',
    # Uncomment the next line for simple clickjacking protection:
    # 'django.middleware.clickjacking.XFrameOptionsMiddleware',
)

Answer 1

我有同样的问题,并通过在您的视图中添加ensure_csrf_cookie装饰器来解决它:

 from django.views.decorators.csrf import ensure_csrf_cookie
 @ensure_csrf_cookie
 def yourView(request):
     #...

它将在浏览器cookie中设置csrftoken,你可以像这样制作ajax

function getCookie(name) {
    var cookieValue = null;
    if (document.cookie && document.cookie != '') {
        var cookies = document.cookie.split(';');
        for (var i = 0; i < cookies.length; i++) {
            var cookie = jQuery.trim(cookies[i]);
            // Does this cookie string begin with the name we want?
            if (cookie.substring(0, name.length + 1) == (name + '=')) {
                cookieValue = decodeURIComponent(cookie.substring(name.length + 1));
                break;
            }
        }
    }
    return cookieValue;
}
function csrfSafeMethod(method) {
    // these HTTP methods do not require CSRF protection
    return (/^(GET|HEAD|OPTIONS|TRACE)$/.test(method));
}
$.ajaxSetup({
    crossDomain: false, // obviates need for sameOrigin test
    beforeSend: function(xhr, settings) {
        if (!csrfSafeMethod(settings.type)) {
            xhr.setRequestHeader("X-CSRFToken", getCookie('csrftoken'));
        }
    }
});
$.ajax({
        url: url,
        type: type,
        async: async,
        data: data,
        error: function (e) {},
        success: function (data) {
                returnFunction(data);
            }
    });

Answer 2

您使用这两种方式将 CSRF 令牌传递给模板处理器

c = {}
c.update(csrf(request))

和RequestContext，一个就够了，请参阅 docs。但是你用错了地方，用于服务“POST”请求。这些请求通常由您的浏览器在填写表单并希望获得结果时发送。

您的浏览器呈现 home.html 向服务器发送 GET 请求，该服务器由

t = get_template('home.html')
html = t.render(ResponseContext({'name':name}))
return HttpResponse(html)

你代码的一部分。在那里你没有使用任何手段来传递 csrf 令牌。因此，当您的模板处理器get_template().render()被调用时，它的上下文中没有标记，因此只需忽略模板中的 {% csrf_token %} 代码。所以你必须要么使用RequestContext在视图的 t.render(...) 部分，在那里传递你的c字典。

您可以在浏览器窗口中检查生成的表单。

更新

在 seetings.py添加一个逗号'django.core.context_processors.csrf'，就像现在一样，它只是连接字符串。

应该：

TEMPLATE_CONTEXT_PROCESSORS = (
    'django.core.context_processors.csrf',
    'django.contrib.auth.context_processors.auth',
    'django.core.context_processors.debug',