当jar明显拥有它时,Java NoClassDefFoundError

Pau*_*jan 1 java classpath noclassdeffounderror

我有一个简单的类从另一个jar导入另一个类.一切都很好,但试图运行它...

$ jar tvf ../../pig-2.1.jar  | grep TupleFact
1641 Mon Feb 02 17:56:32 UTC 2009 org/apache/pig/data/DefaultTupleFactory.class
2289 Mon Feb 02 17:56:30 UTC 2009 org/apache/pig/data/TupleFactory.class
$ javac ../src/Convert.java -classpath `echo ../lib/* ../../lib/* | sed 's/ /:/g'`
$ java Convert -classpath `echo ../lib/* ../../lib/* | sed 's/ /:/g'`
Exception in thread "main" java.lang.NoClassDefFoundError: org/apache/pig/data/TupleFactory
        at Convert.<clinit>(Convert.java:31)
Caused by: java.lang.ClassNotFoundException: org.apache.pig.data.TupleFactory
        at java.net.URLClassLoader$1.run(URLClassLoader.java:200)
        at java.security.AccessController.doPrivileged(Native Method)
        at java.net.URLClassLoader.findClass(URLClassLoader.java:188)
        at java.lang.ClassLoader.loadClass(ClassLoader.java:306)
        at sun.misc.Launcher$AppClassLoader.loadClass(Launcher.java:276)
        at java.lang.ClassLoader.loadClass(ClassLoader.java:251)
        at java.lang.ClassLoader.loadClassInternal(ClassLoader.java:319)
        ... 1 more
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有任何想法吗?你是如何开始调试的?

Ste*_*n C 8

我认为问题在于您运行命令的方式:

java Convert -classpath `echo ../lib/* ../../lib/* | sed 's/ /:/g'`
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应该

java  -classpath `echo ../lib/* ../../lib/* | sed 's/ /:/g'` Convert
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"java"命令的命令行语法是:

javac [ <options for the JVM> ... ] <classname> [ <application args> ... ]
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如果在类名后面加上"-classpath"选项,它将被视为应用程序参数,您将使用默认的类路径执行应用程序.