如何在Python中一次运行2台服务器？

Question

我需要使用线程模块在Python中同时运行2个服务器,但是要调用函数run(),第一个服务器正在运行,但第二个服务器直到第一个服务器结束才运行.
这是源代码:

import os
import sys
import threading

n_server = 0
n_server_lock = threading.Lock()

class ServersThread(threading.Thread):
    def __init__(self):
        threading.Thread.__init__(self)
        self.start()
        self.join()

    def run(self):
        global n_server, n_server_lock

        if n_server == 0:
            n_server_lock.acquire()
            n_server += 1
            n_server_lock.release()

            print(['MainServer'])

            # This is the first server class    
            main_server = MainServer()
        elif n_server == 1:
            n_server_lock.acquire()
            n_server += 1
            n_server_lock.release()

            print (['DownloadServer'])

            # This is the second server class
            download_server = DownloadServer()

if __name__ == "__main__":
    servers = []

    for i in range(2):
        servers += [ServersThread()]

当我调用服务器类时,它会自动运行无限循环.
那么如何一次运行2台服务器呢？

---

非常感谢您对Fragsworth的帮助,我只是测试新结构并且工作完美.MainServer和DownloadServer类继承自threading.Thread并在run()内运行无限循环.最后我像你说的那样打电话给服务器.

Answer 1

你不想join()在你的__init__功能.这导致系统阻塞,直到每个线程完成.

我建议你重新构建你的程序,这样你的主要功能看起来更像是:

if name == "__main__":
    servers = [MainServer(), DownloadServer()]
    for s in servers:
        s.start()
    for s in servers:
        s.join()        

也就是说,创建一个单独的线程类为您MainServer和DownloadServer,然后让他们从异步主流程开始,之后加入.