**PHP**
$datearr = explode("/", $cutOff);
$month = $datearr[0];
$day = $datearr[1];
$year = $datearr[2];
$mainten = "MAINTENANCE";
$pad=' ';
$maint = str_pad($mainten, 20, $pad);
$string = $cduid . $maint . $inarea . $year . $month . $day . "\n";
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我试图将此字符串解析为服务器,并且$ maint必须用右边的空格填充.我也试过.....
$datearr = explode("/", $cutOff);
$month = $datearr[0];
$day = $datearr[1];
$year = $datearr[2];
$mainten = "MAINTENANCE";
$maint = str_pad($mainten, 20);
$string = $cduid . $maint . $inarea . $year . $month . $day . "\n";
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当我回显$ string $ maint时,右边只有1个空格.如果我替换$ pad =''; with $ pad ='.';; 我得到了正确的结果,但我需要它是空格.
我在这里错过了什么?
Leg*_*nar 16
在HTML中,您只能显示一个空格,但通常在源中有空格数,如您所愿.
&nbps; 将无法使用str_pad,因为它有6个字符(在HTML中只有1个字符),但对于str_pad,它将失败.
只有一种方法,如何做,你必须填充一些字符(即.~),然后替换它
$maint = str_replace('~', ' ', str_pad($mainten, 20, '~')); // just use some character you know isn't in your string
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这将是100%的工作.