如何破坏Ruby对象？

Question

如何破坏Ruby对象？

假设有一个简单的对象:

object = Object.new

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据我所知,这会在内存(RAM)中创建对象.

有没有办法从RAM中删除此对象？

Answer 1

Vid*_*dya 25

除了黑客底层的C代码,没有.垃圾收集由运行时管理,因此您不必担心它.这是Ruby 2.0中算法的一个不错的参考.

一旦你没有对内存中的对象的引用,垃圾收集器就会开始工作.你应该没事.

所以,删除引用我应该这样做:`object = nil`,对吗？ (2认同)
对于其他任何查看此内容的人,您将无法简单地使用object = nil来清除内存.即GC不等待你做object = nil然后立即释放内存.它将按照自己的条件进行. (2认同)

Answer 2

vgo*_*off 15

简单的答案是,让GC(垃圾收集器)完成它的工作.

当你准备摆脱那个参考时,就这样做object = nil.并且不要参考object.

垃圾收集器最终会收集并清除引用.

(from ruby site)
=== Implementation from GC
------------------------------------------------------------------------------
  GC.start                     -> nil
  GC.start(full_mark: true, immediate_sweep: true)           -> nil

------------------------------------------------------------------------------

Initiates garbage collection, unless manually disabled.

This method is defined with keyword arguments that default to true:

  def GC.start(full_mark: true, immediate_sweep: true); end

Use full_mark: false to perform a minor GC. Use immediate_sweep: false to
defer sweeping (use lazy sweep).

Note: These keyword arguments are implementation and version dependent. They
are not guaranteed to be future-compatible, and may be ignored if the
underlying implementation does not support them.

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