Cho*_*oos 9 sql-server sql-server-2008
我试图从select语句插入一个表,并添加其他参数到行,如下所示 -
SELECT
Appt_ID,
Pracitioner_ID,
Appt_Book_ID,
Start_Time,
UR_NO,
[Type],
[Description]
FROM @TempWaiting,
@EndTime,
@PatientID,
@Title,
@FirstName,
@LastName,
@Surname,
@DOB
INTO PS_WAITING_LIST(Appt_ID,
Pracitioner_ID,
Appt_Book_ID,
Start_Time,
UR_NO,
[Type],
[Description],
End_Time,
Patient_ID,
Title,
First_Name,
Middle_Name,
Surname,
DOB)
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这是在一个存储过程中,所有它说是INTO后的错误.
我也尝试重写它 -
insert into PS_WAITING_LIST (
Appt_ID,
Pracitioner_ID,
Appt_Book_ID,
Start_Time,
UR_NO,
[Type],
[Description],
End_Time,
Patient_ID,
Title,
First_Name,
Middle_Name,
Surname,
DOB)
SELECT
Appt_ID,
Pracitioner_ID,
Appt_Book_ID,
Start_Time,
UR_NO,
[Type],
[Description]
FROM @TempWaiting,
@EndTime,
@PatientID,
@Title,
@FirstName,
@LastName,
@Surname,
@DOB
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这会抛出一个错误,指出选择值的数量必须与插入列的数量匹配.显然那不是.
我也试过Insert into table(col1,col2 ..)Select*from(select(...),col3,col9)
jue*_*n d 18
通常它的工作原理如下
insert into your_table (col1, col2, col3)
select some_column, @aVariable, 'static_string'
from another_table
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