在中间件中获取路由定义

Question

有谁知道是否有可能获得用于触发路线的路径？

例如,假设我有这个:

app.get('/user/:id', function(req, res) {});

使用以下简单的中间件

function(req, res, next) {
     req.?
});

我希望能够进入/user/:id中间件,但事实并非如此req.url.

Answer 1

你想要的是什么req.route.path.

例如:

app.get('/user/:id?', function(req, res){
  console.log(req.route);
});

// outputs something like

{ path: '/user/:id?',
  method: 'get',
  callbacks: [ [Function] ],
  keys: [ { name: 'id', optional: true } ],
  regexp: /^\/user(?:\/([^\/]+?))?\/?$/i,
  params: [ id: '12' ] }

http://expressjs.com/api.html#req.route

编辑:

正如评论中所解释的那样,进入req.route中间件很困难/很困难.路由器中间件是填充req.route对象的中间件,它可能比您正在开发的中间件低.

通过这种方式,req.route只有req在Express自身执行之前,您可以使用挂钩到路由器中间件来解析它.

Answer 2

FWIW,另外两个选择:

// this will only be called *after* the request has been handled
app.use(function(req, res, next) {
  res.on('finish', function() {
    console.log('R', req.route);
  });
  next();
});

// use the middleware on specific requests only
var middleware = function(req, res, next) {
  console.log('R', req.route);
  next();
};
app.get('/user/:id?', middleware, function(req, res) { ... });