如何访问C#函数,它将指针作为C#的输入参数

use*_*173 5 c# c++ pointers

using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;
using System.Runtime.InteropServices;

namespace PatternSequencer
{
    class Version
    {
        public string majorVersion;
        public string minorVersion;

        ushort* pmajorVersion;
        ushort* pminorVersion;
        ulong status;

        [DllImport(@"c:\DOcuments\Myapp.dll", CallingConvention = CallingConvention.Cdecl, EntryPoint = "SRX_DllVersion")]
        public static extern ulong SRX_DllVersion(ushort* pmajorVersion, ushort* pminorVersion);


        public Version()
        {
            status = SRX_DllVersion(&pmajorVersion, &pminorVersion);
            if (status)
            {
                majorVersion = "1 - " + *pmajorVersion;
                minorVersion = "1 - " + *pminorVersion;
            }
            else
            {
                majorVersion = "0 - " + *pmajorVersion;
                minorVersion = "0 - " + *pminorVersion;
            }
        }
    }
}
Run Code Online (Sandbox Code Playgroud)

它会抛出错误指针,固定大小的缓冲区只能在不安全的上下文中使用.如何将指针传递给C++ DLL?我是C#的新手,请帮助我

小智 8

而不是使用unsafe上下文尝试:

[DllImport(@"c:\FreeStyleBuild\BERTScope\Release\Bin\BitAlyzerDLL.dll", CallingConvention = CallingConvention.Cdecl, EntryPoint = "SRX_DllVersion")]
public static extern ulong SRX_DllVersion(out ushort pmajorVersion, out ushort pminorVersion);
Run Code Online (Sandbox Code Playgroud)

拨打电话:

ushort major, minor;
SRX_DllVersion(out major, out minor);
Run Code Online (Sandbox Code Playgroud)

我假设SRX_DllVersion参数仅输出,如果不改变outref.

unsafe尽可能避免使用代码.