Jes*_*ess 12 sms android intentfilter broadcastreceiver
我正在尝试编写一个试图接收SMS消息并处理它们的简单应用程序.我已经按照了几个教程,但是我无处可去,当我向模拟器发送短信时,Intent似乎永远不会被解雇.
这是我的意图:
package com.neocodenetworks.smsfwd;
import android.content.*;
import android.os.Bundle;
import android.telephony.*;
import android.util.Log;
public class SmsReciever extends BroadcastReceiver {
private static final String SMS_RECEIVED = "android.provider.Telephony.SMS_RECEIVED";
private static final String TAG = "smsfwd";
@Override
public void onReceive(Context context, Intent intent) {
Log.i(TAG, "Intent recieved: " + intent.getAction());
if (intent.getAction() == SMS_RECEIVED) {
Bundle bundle = intent.getExtras();
if (bundle != null) {
Object[] pdus = (Object[])bundle.get("pdus");
final SmsMessage[] messages = new SmsMessage[pdus.length];
for (int i = 0; i < pdus.length; i++) {
messages[i] = SmsMessage.createFromPdu((byte[])pdus[i]);
}
if (messages.length > -1) {
Log.i(TAG, "Message recieved: " + messages[0].getMessageBody());
NetComm.SendMessage("me", messages[0].getOriginatingAddress(), messages[0].getMessageBody());
}
}
}
}
}
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这是我的AndroidManifest.xml:
<?xml version="1.0" encoding="utf-8"?>
<manifest xmlns:android="http://schemas.android.com/apk/res/android"
package="com.neocodenetworks.smsfwd"
android:versionCode="1"
android:versionName="1.0">
<application android:icon="@drawable/icon" android:label="@string/app_name" android:debuggable="true">
<receiver android:name=".SmsReciever">
<intent-filter>
<action android:name="android.provider.telephony.SMS_RECIEVED"></action>
</intent-filter>
</receiver>
</application>
<uses-sdk android:minSdkVersion="6" />
<uses-permission android:name="android.permission.INTERNET"></uses-permission>
<uses-permission android:name="android.permission.RECEIVE_SMS"></uses-permission>
</manifest>
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对于出了什么问题,我真的很感激.我刚刚开始进入Android开发阶段,但我认为我的头脑已经被大部分包围了.在监视模拟器的logcat时,日志事件永远不会出现,并且调试断点永远不会被击中,所以我感觉它在我的intent过滤器中的某个位置.
我在Android 2.0.1上运行它.
Sam*_*muh 10
我觉得你的清单看起来还不错; 问题在于:
if (intent.getAction() == SMS_RECEIVED) {
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我认为它应该是: intent.getAction().equals(ACTION)
希望有所帮助..