gst*_*low 1 java spring mocking spring-mvc spring-test
我有这个html spring形式:
<form:form action="addVacancy" modelAttribute="myVacancy">
<form:label path="name">name</form:label>
<form:input path="name" ></form:input>
<form:errors path="name" cssClass="error" />
<br>
<form:label path="description">description</form:label>
<form:input path="description" id="nameInput"></form:input>
<form:errors path="description" cssClass="error" />
<br>
<form:label path="date">date</form:label>
<input type="date" name="date" />
<form:errors path="date" cssClass="error" />
<br>
<input type="submit" value="add" />
</form:form>
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我通过这种方法处理这个表单:
@RequestMapping("/addVacancy")
public ModelAndView addVacancy(@ModelAttribute("myVacancy") @Valid Vacancy vacancy,BindingResult result, Model model,RedirectAttributes redirectAttributes){
if(result.hasErrors()){
model.addAttribute("message","validation error");
return new ModelAndView("vacancyDetailsAdd");
}
vacancyService.add(vacancy);
ModelAndView mv = new ModelAndView("redirect:goToVacancyDetails");
mv.addObject("idVacancy", vacancy.getId());
redirectAttributes.addAttribute("message", "added correctly at "+ new Date());
return mv;
}
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如何提交相同的请求,这是在提交表单后获得的.这必须通过MockMvc完成.
@Test
public void testMethod(){
MockHttpServletRequestBuilder request = MockMvcRequestBuilders.get("/addVacancy");
//what must I write here?
ResultActions result = mockMvc.perform(request);
}
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我很困惑.
当浏览器需要提交表单时,它通常将表单<input>字段序列化为url编码的参数.因此,当您想要模拟a时HttpServletRequest,需要将相同的参数添加到请求中.
request.param("name", "some value")
.param("description", "description value")
.param("date", "some acceptable representation of date");
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在DispatcherServlet将使用这些参数来创建一个Vacancy实例作为参数传递到您的处理方法.
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