在matlab我用
a=[1,4,6]
b=[1,2,3]
corr(a,b)
返回.9934.我尝试过,numpy.correlate但它会返回完全不同的东西.获得两个向量的相关性的最简单方法是什么?
Hoo*_*ked 141
文档表明这numpy.correlate不是你想要的:
numpy.correlate(a, v, mode='valid', old_behavior=False)[source]
  Cross-correlation of two 1-dimensional sequences.
  This function computes the correlation as generally defined in signal processing texts:
     z[k] = sum_n a[n] * conj(v[n+k])
  with a and v sequences being zero-padded where necessary and conj being the conjugate.
相反,正如其他评论所暗示的那样,您正在寻找Pearson相关系数.要用scipy尝试这样做:
from scipy.stats.stats import pearsonr   
a = [1,4,6]
b = [1,2,3]   
print pearsonr(a,b)
这给了
(0.99339926779878274, 0.073186395040328034)
您还可以使用numpy.corrcoef:
import numpy
print numpy.corrcoef(a,b)
这给出了:
[[ 1.          0.99339927]
 [ 0.99339927  1.        ]]
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