gog*_*net 37 angularjs angular-ui angularjs-ng-repeat
假设我收到一个包含15个以上对象的对象文字,我需要在一个漂亮的布局中显示它们(并非所有的连续),控制何时应该断行/页面应该结束的最有效的方法是什么?
现在我在表行上使用ng-repeat,结果是一个带有一列的长薄表.
编辑以澄清.可以在对象/更多参数中包含对象.这是我的对象:
$scope.zones = [
{"name": "Zone 1",
"activity": "1"},
{"name": "Zone 2",
"activity": "1"},
{"name": "Zone 3",
"activity": "0"},
{"name": "Zone 4",
"activity": "0"},
{"name": "Zone 5",
"activity": "0"},
{"name": "Zone 6",
"activity": "0"},
{"name": "Zone 7",
"activity": "1"},
{"name": "Zone 8",
"activity": "0"},
{"name": "Zone 9",
"activity": "0"},
{"name": "Zone 10",
"activity": "0"},
{"name": "Zone 11",
"activity": "1"},
{"name": "Zone 12",
"activity": "1"},
{"name": "Zone 13",
"activity": "0"},
{"name": "Zone 14",
"activity": "0"},
{"name": "Zone 15",
"activity": "1"},
];
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Max*_*tin 71
我会使用表并在控制器中实现分页来控制显示的数量和按钮移动到下一页.这个小提琴可能会帮助你.
<table class="table table-striped table-condensed table-hover">
<thead>
<tr>
<th class="id">Id <a ng-click="sort_by('id')"><i class="icon-sort"></i></a></th>
<th class="name">Name <a ng-click="sort_by('name')"><i class="icon-sort"></i></a></th>
<th class="description">Description <a ng-click="sort_by('description')"><i class="icon-sort"></i></a></th>
<th class="field3">Field 3 <a ng-click="sort_by('field3')"><i class="icon-sort"></i></a></th>
<th class="field4">Field 4 <a ng-click="sort_by('field4')"><i class="icon-sort"></i></a></th>
<th class="field5">Field 5 <a ng-click="sort_by('field5')"><i class="icon-sort"></i></a></th>
</tr>
</thead>
<tfoot>
<td colspan="6">
<div class="pagination pull-right">
<ul>
<li ng-class="{disabled: currentPage == 0}">
<a href ng-click="prevPage()">« Prev</a>
</li>
<li ng-repeat="n in range(pagedItems.length)"
ng-class="{active: n == currentPage}"
ng-click="setPage()">
<a href ng-bind="n + 1">1</a>
</li>
<li ng-class="{disabled: currentPage == pagedItems.length - 1}">
<a href ng-click="nextPage()">Next »</a>
</li>
</ul>
</div>
</td>
</tfoot>
<tbody>
<tr ng-repeat="item in pagedItems[currentPage] | orderBy:sortingOrder:reverse">
<td>{{item.id}}</td>
<td>{{item.name}}</td>
<td>{{item.description}}</td>
<td>{{item.field3}}</td>
<td>{{item.field4}}</td>
<td>{{item.field5}}</td>
</tr>
</tbody>
</table>
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小提琴示例中的$ scope.range应为:
$scope.range = function (size,start, end) {
var ret = [];
console.log(size,start, end);
if (size < end) {
end = size;
if(size<$scope.gap){
start = 0;
}else{
start = size-$scope.gap;
}
}
for (var i = start; i < end; i++) {
ret.push(i);
}
console.log(ret);
return ret;
};
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Nun*_*lva 13
我使用这个解决方案:
因为我使用它ng-repeat="obj in objects | filter : paginate"
来过滤行,所以更简洁一些.还使它与$资源一起使用:
http://plnkr.co/edit/79yrgwiwvan3bAG5SnKx?p=preview
这是我的解决方案.@Maxim Shoustin的解决方案在排序方面存在一些问题.我还将整个事情包装成一个指令.唯一的依赖是UI.Bootstrap.pagination,它在分页方面做得很好.
这是掠夺者
在这里我已经解决了我的angularJS分页问题,在服务器端进行了一些调整+查看结束你可以检查代码它会更有效率.我所要做的就是放两个值的起始编号和结束编号,它将代表返回的json数组的索引.
这是棱角分明的
var refresh = function () {
$('.loading').show();
$http.get('http://put.php?OutputType=JSON&r=all&s=' + $scope.CountStart + '&l=' + $scope.CountEnd).success(function (response) {
$scope.devices = response;
$('.loading').hide();
});
};
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如果你仔细看到$ scope.CountStart和$ scope.CountStart是我传递api的两个参数
这是下一个按钮的代码
$scope.nextPage = function () {
$('.loading').css("display", "block");
$scope.nextPageDisabled();
if ($scope.currentPage >= 0) {
$scope.currentPage++;
$scope.CountStart = $scope.CountStart + $scope.DevicePerPage;
$scope.CountEnd = $scope.CountEnd + $scope.DevicePerPage;
refresh();
}
};
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这是前一个按钮的代码
$scope.prevPage = function () {
$('.loading').css("display", "block");
$scope.nextPageDisabled();
if ($scope.currentPage > 0) {
$scope.currentPage--;
$scope.CountStart = $scope.CountStart - $scope.DevicePerPage;
$scope.CountEnd = $scope.CountEnd - $scope.DevicePerPage;
refresh();
}
};
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如果页码为零,我的上一个按钮将被停用
$scope.nextPageDisabled = function () {
console.log($scope.currentPage);
if ($scope.currentPage === 0) {
return false;
} else {
return true;
}
};
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