在Ruby中更优雅的方式来做到这一点

Question

我从Ruby开始,并且每天都在寻找新的,更短,更优雅的方法来编写代码.

在解决Project Euler问题时,我写了很多代码

if best_score < current_score
  best_score = current_score
end

是否有更优雅的方式来写这个？

Answer 1

best_score = [best_score, current_score].max

见:可数.最大

免责声明:虽然这是一个更具可读性(imho),但性能较差:

require 'benchmark'

best_score, current_score, n = 1000, 2000, 100_000

Benchmark.bm do |x|
  x.report { n.times do best_score = [best_score, current_score].max end }
  x.report { n.times do 
    best_score = current_score if best_score < current_score 
  end }
end

将导致(与红宝石1.8.6(2008-08-11 patchlevel 287)):

    user     system      total        real
0.160000   0.000000   0.160000 (  0.160333)
0.030000   0.000000   0.030000 (  0.030578)

Answer 2

这可以在一行上完成:

best_score = current_score if best_score < current_score

Answer 3

也许一个班轮？

best_score = current_score if best_score < current_score