如何将日期差异作为具有毫秒精度的浮点数

Question

public static void main(String[] args) throws InterruptedException{
    long sTime =  new Date().getTime();
    Thread.sleep(3234);
    long eTime =  new Date().getTime();
    float diff = ((eTime-sTime)/1000);
    System.out.println(diff);
}

在上面的代码中,我期望输出为3.234,但它是3.0.我想要两秒之间的精确差异,只有一小部分.

Answer 1

你正在做一个整体划分而不是一个浮点划分.试试这个:

float diff = ((float)(eTime-sTime)/1000.0);

当您使用longs时,我进一步建议您使用double数据类型以获得更高的精度:

double diff = ((double)(eTime-sTime)/1000.0);