MySql - 首先按字符串值排序

Question

我有下表Foobar看起来像这样:

+----+-------------+
| ID | Description |
+----+-------------+
| 12 | aab         |
+----+-------------+
| 13 | fff         |
+----+-------------+
| 14 | fff         |
+----+-------------+
| 15 | xab         |
+----+-------------+

我想要的是按顺序打印出所有描述.但是我首先要把值"fff"放在最顶层.换句话说,输出应如下:fff,fff,aab,xab.

所以很简单:"SELECT foobar.description FROM foobar ORDER BY foobar.description ASC"将无效.

Answer 1

在MySQL中这是有效的

SELECT foobar.description 
FROM foobar 
ORDER BY foobar.description <> 'fff',
         foobar.description ASC

但一般来说你也可以使用 case

SELECT foobar.description 
FROM foobar 
ORDER BY case when foobar.description = 'fff' then 1 else 2 end,
         foobar.description ASC