Job*_*Joy 807 mysql information-schema
我有2-3个不同的列名称,我想在整个数据库中查找并列出所有具有这些列的表.任何简单的脚本?
Ken*_*Ken 1316
要获取包含列columnA或ColumnB数据库的所有表YourDatabase:
SELECT DISTINCT TABLE_NAME
FROM INFORMATION_SCHEMA.COLUMNS
WHERE COLUMN_NAME IN ('columnA','ColumnB')
AND TABLE_SCHEMA='YourDatabase';
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GSe*_*erg 164
SELECT TABLE_NAME, COLUMN_NAME
FROM INFORMATION_SCHEMA.COLUMNS
WHERE COLUMN_NAME LIKE '%wild%';
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Xma*_*cal 42
更简单地在一行SQL中完成:
SELECT * FROM information_schema.columns WHERE column_name = 'column_name';
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小智 36
SELECT DISTINCT TABLE_NAME, COLUMN_NAME
FROM INFORMATION_SCHEMA.COLUMNS
WHERE column_name LIKE 'employee%'
AND TABLE_SCHEMA='YourDatabase'
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Rad*_*ris 18
在没有的information_schema版本(旧版本或某些ndb)中,您可以转储表结构并手动搜索列.
mysqldump -h$host -u$user -p$pass --compact --no-data --all-databases > some_file.sql
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现在some_file.sql使用首选文本编辑器搜索列名,或使用一些漂亮的awk脚本.
还有一个简单的sed脚本来查找列,只需将COLUMN_NAME替换为您的:
sed -n '/^USE/{h};/^CREATE/{H;x;s/\nCREATE.*\n/\n/;x};/COLUMN_NAME/{x;p};' <some_file.sql
USE `DATABASE_NAME`;
CREATE TABLE `TABLE_NAME` (
`COLUMN_NAME` varchar(10) NOT NULL,
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您可以直接在sed中管道转储,但这很简单.
ouc*_*cil 11
对于那些搜索相反的人,即查找不包含某个列名的表,这里是查询...
SELECT DISTINCT TABLE_NAME FROM information_schema.columns WHERE
TABLE_SCHEMA = 'your_db_name' AND TABLE_NAME NOT IN (SELECT DISTINCT
TABLE_NAME FROM information_schema.columns WHERE column_name =
'column_name' AND TABLE_SCHEMA = 'your_db_name');
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当我们开始慢慢实现InnoDB特殊ai_col列的使用并且需要弄清楚我们的200个表中哪些尚未升级时,这非常方便.
小智 8
使用这一行查询。将所需的列名替换为您的列名。
SELECT TABLE_NAME FROM information_schema.columns WHERE column_name = 'desired_column_name';
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如果您想" 仅获取所有表 ",请使用此查询:
SELECT TABLE_NAME
FROM INFORMATION_SCHEMA.TABLES
WHERE TABLE_NAME like '%'
and TABLE_SCHEMA = 'tresbu_lk'
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如果您想要" 获取包含列的所有表 ",请使用以下查询:
SELECT DISTINCT TABLE_NAME, COLUMN_NAME
FROM INFORMATION_SCHEMA.COLUMNS
WHERE column_name LIKE '%'
AND TABLE_SCHEMA='tresbu_lk'
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select distinct table_name
from information_schema.columns
where column_name in ('ColumnA')
and table_schema='YourDatabase';
and table_name in
(
select distinct table_name
from information_schema.columns
where column_name in ('ColumnB')
and table_schema='YourDatabase';
);
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^^ 将获得带有 ColumnA和ColumnB 而不是 ColumnA或ColumnB的表格,就像接受的答案
小智 5
SELECT DISTINCT TABLE_NAME FROM INFORMATION_SCHEMA.COLUMNS WHERE COLUMN_NAME LIKE '%city_id%' AND TABLE_SCHEMA='database'
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