我有一个XSD文件,将其转换为ecore模型并从中生成模型代码。现在,我想为该架构加载一个xml文件,但是继续出现错误:
org.eclipse.emf.ecore.xmi.PackageNotFoundException:
Package with uri 'null' not found.
(file:/C:/Users/mboeschen/safety/devel/eclipse_plugins...
/de.offis.etas.load/examples/minimal.xml, 2, 7)
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因为这是直接在我的xml文件中的根标记之后,所以我怀疑在读取根标记后出现了问题。
我的代码如下:
public static void main(String[] args) throws IOException {
MinimalPackage.eINSTANCE.eClass();
MinimalPackage packageInstance = MinimalPackage.eINSTANCE;
Resource.Factory.Registry reg = Resource.Factory.Registry.INSTANCE;
Map<String, Object> m = reg.getExtensionToFactoryMap();
m.put("*", new XMLResourceFactoryImpl());
// Obtain a new resource set
ResourceSet resSet = new ResourceSetImpl();
resSet.setResourceFactoryRegistry(reg);
resSet.getPackageRegistry().put(MinimalPackage.eNS_URI,
MinimalPackage.eINSTANCE);
resSet.getPackageRegistry().put(null,
MinimalPackage.eINSTANCE);
// Get the resource
URI uri = URI
.createFileURI("C:/Users/mboeschen/safety/devel/eclipse_plugins...
/de.offis.etas.load/examples/minimal.xml");
Resource resource = resSet.getResource(uri, true);
RootType r = (RootType) resource.getContents().get(0);
System.out.println(r);
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模式文件如下所示:
org.eclipse.emf.ecore.xmi.PackageNotFoundException:
Package with uri 'null' not found.
(file:/C:/Users/mboeschen/safety/devel/eclipse_plugins...
/de.offis.etas.load/examples/minimal.xml, 2, 7)
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这是xml文件:
public static void main(String[] args) throws IOException {
MinimalPackage.eINSTANCE.eClass();
MinimalPackage packageInstance = MinimalPackage.eINSTANCE;
Resource.Factory.Registry reg = Resource.Factory.Registry.INSTANCE;
Map<String, Object> m = reg.getExtensionToFactoryMap();
m.put("*", new XMLResourceFactoryImpl());
// Obtain a new resource set
ResourceSet resSet = new ResourceSetImpl();
resSet.setResourceFactoryRegistry(reg);
resSet.getPackageRegistry().put(MinimalPackage.eNS_URI,
MinimalPackage.eINSTANCE);
resSet.getPackageRegistry().put(null,
MinimalPackage.eINSTANCE);
// Get the resource
URI uri = URI
.createFileURI("C:/Users/mboeschen/safety/devel/eclipse_plugins...
/de.offis.etas.load/examples/minimal.xml");
Resource resource = resSet.getResource(uri, true);
RootType r = (RootType) resource.getContents().get(0);
System.out.println(r);
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任何想法在这里发生了什么?任何帮助表示赞赏!
小智 2
当您生成模型时,您可能会得到一个生成的 [YourModelName]ResourceFactoryImpl 类。我的 KML 编辑器也遇到了同样的问题,这就是我解决它的方法:
public class OgckmlResourceFactoryImpl extends ResourceFactoryImpl {
...
/**
* Creates an instance of the resource.
* <!-- begin-user-doc -->
* <!-- end-user-doc -->
* @generated NOT
*/
@Override
public Resource createResource(URI uri) {
XMLResource result = new OgckmlResourceImpl(uri);
setupOptions(result);
return result;
}
protected void setupOptions(XMLResource result)
{
...
result.getDefaultLoadOptions().put(XMLResource.OPTION_EXTENDED_META_DATA, new BasicExtendedMetaData()
{
private static final String NAMESPACE_GOOGLE_EXT_2_2 = "http://www.google.com/kml/ext/2.2";
private static final String NAMESPACE_OPENGIS_2_2 = "http://www.opengis.net/kml/2.2";
private static final String NAMESPACE_DEFAULT = NAMESPACE_OPENGIS_2_2;
@Override
public EPackage getPackage(String namespace) {
if(namespace==null){
namespace = NAMESPACE_DEFAULT;
}
return super.getPackage(namespace);
}
@Override
public EStructuralFeature getElement(String namespace, String name)
{
if (feature == null)
feature = super.getElement(NAMESPACE_OPENGIS_2_2, name);
if (feature == null)
feature = super.getElement(NAMESPACE_GOOGLE_EXT_2_2, name);
return feature;
}
});
...
}
}
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