使用Ruby gsub转义linux路径名中的空格

Question

我试图逃避Linux路径中的空间.但是,每当我试图逃避反斜杠时,我最终会得到一个双斜线.

示例路径:

/mnt/drive/site/usa/1201 East/1201 East Invoice.pdf

所以我可以在Linux中使用它我想逃避它:

/mnt/drive/site/usa/1201\ East/1201\ East\ Invoice.pdf

所以我正在尝试这个:

backup_item.gsub("\s", "\\\s")

但是我得到了意想不到的输出

/mnt/drive/site/usa/1201\\ East/1201\\ East\\ Invoice.pdf

Answer 1

斯特凡是对的; 我只是想指出,如果你必须为shell使用转义字符串,你应该检查Shellwords::shellescape:

require 'shellwords'

puts Shellwords.shellescape "/mnt/drive/site/usa/1201 East/1201 East Invoice.pdf"
# prints /mnt/drive/site/usa/1201\ East/1201\ East\ Invoice.pdf

# or

puts "/mnt/drive/site/usa/1201 East/1201 East Invoice.pdf".shellescape
# prints /mnt/drive/site/usa/1201\ East/1201\ East\ Invoice.pdf

# or (as reported by @hagello)
puts shellwords.escape "/mnt/drive/site/usa/1201 East/1201 East Invoice.pdf"
# prints /mnt/drive/site/usa/1201\ East/1201\ East\ Invoice.pdf

Answer 2

这是字符串的inspect值,"str的可打印版本,用引号括起来,特殊字符被转义":

quoted = "path/to/file with spaces".gsub(/ /, '\ ')
=> "path/to/file\\ with\\ spaces"

只需打印字符串:

puts quoted

输出:

path/to/file\ with\ spaces