从requests.exceptions.HTTPError获取HTTP错误代码

Question

我抓住这样的例外,

def get_url_fp(image_url, request_kwargs=None):
    response = requests.get(some_url, **request_kwargs)
    response.raise_for_status()
    return response.raw


try:
   a = "http://example.com"
   fp = get_url_fp(a)

except HTTPError as e:
    # Need to check its an 404, 503, 500, 403 etc.

Answer 1

的HTTPError携带Response用它目的:

def get_url_fp(image_url, request_kwargs=None):
    response = requests.get(some_url, **request_kwargs)
    response.raise_for_status()
    return response.raw


try:
    a = "http://example.com"
    fp = get_url_fp(a)

except HTTPError as e:
    # Need to check its an 404, 503, 500, 403 etc.
    status_code = e.response.status_code

Answer 2

如果您只需要 status_code 或消息错误。您可以使用此代码：

try:
  [YOUR CODE]
except requests.exceptions.HTTPError as err:
  print(err.response.status_code)
  print(err.response.text)

参考：requests.exceptions的源代码