C的分段错误

Question

我的程序是一个简单的"岩纸剪刀蜥蜴Spock"​​程序,我想添加一个2人或1个玩家与计算机选项.这是我编写选择部分的方式:

printf("1.One player OR 2.Two players?\n");
scanf("%d", playerNum);
//input section
printf("1.rock\n2.paper\n3.scissor\n4.spock\n5.lizard\n");
printf("player A enter a choice ");
scanf ("%d", &choiceA);
if (playerNum == 2)
{
    printf("1.rock\n2.paper\n3.scissor\n4.spock\n5.lizard\n");
    printf("player B enter a choice ");
    scanf ("%d", &choiceB);
}
else if (playerNum == 1)
{
    choiceB = 1+rand()%5;
    printf("The computer has picked %d", choiceB);
}

当我运行程序时,它在我输入值后立即给出了分段错误playerNum.
上面使用的所有变量都声明为整数.

Answer 1

在传递类型参数时,您scanf期望一个类型的参数. 你在论证中缺少. int *int
&scanf

scanf("%d", playerNum);
           ^
           |
        & is missing.  

将此更改为

scanf("%d", &playerNum);