Jac*_*cob 5 php mysql sql subquery prestashop
我知道这很复杂,但我真诚地希望有人能检查一下。我制作了简短版本(以更好地理解问题)和完整版本(使用原始 SQL)
[TABLE A] [TABLE B]
|1|a|b| |1|x
|2|c|d| |1|y
|3| | | |2|z
|5| | | |2|v
|4|w
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我怎样才能让 MySQL 查询得到这样的行:
1|a|b|x|y
2|c|d|z|v
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A 的 2 列和 B 的 2 行作为列,只有键 1 和 2,没有空结果
子查询?
我试图在一行中从 Prestashop db 获取:
id_product、ean13 和 upc 很容易得到,因为它是 ps_product 表中的一行。为了获得功能,我使用了子查询(JOIN 没有成功)。
所以,我选择了 id_product, ean13, upc, (subquery1) 作为 code1, (subquery2) 作为 code2。然后我需要抛出空行。但不能只将 code1 或 code2 放在 WHERE 中。为了使它工作,我必须将所有内容都放在子查询中。
此代码WORKS,但它是非常丑陋的,我敢打赌,这应该怎样做。
我怎样才能让它更好?
SELECT * FROM(
SELECT
p.id_product as idp, p.ean13 as ean13, p.upc as upc, (
SELECT
fvl.value
FROM
`ps_feature_product` fp
LEFT JOIN
`ps_feature_value_lang` fvl ON (fp.id_feature_value = fvl.id_feature_value)
WHERE fp.id_feature = 24 AND fp.id_product = idp
) AS code1, (
SELECT
fvl.value
FROM
`ps_feature_product` fp
LEFT JOIN
`ps_feature_value_lang` fvl ON (fp.id_feature_value = fvl.id_feature_value)
WHERE fp.id_feature = 25 AND fp.id_product = idp
) AS code2,
m.name
FROM
`ps_product` p
LEFT JOIN
`ps_manufacturer` m ON (p.id_manufacturer = m.id_manufacturer)
) mainq
WHERE
ean13 != '' OR upc != '' OR code1 IS NOT NULL OR code2 IS NOT NULL
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小智 3
create table tablea
( id int,
col1 varchar(1),
col2 varchar(1));
create table tableb
( id int,
feature int,
cola varchar(1));
insert into tablea (id, col1, col2)
select 1,'a','b' union
select 2,'c','d' union
select 3,null,null union
select 5,null,null;
insert into tableb (id, feature, cola)
select 1,24,'x' union
select 1,25,'y' union
select 2,24,'z' union
select 2,25,'v' union
select 4,24,'w';
select a.id, a.col1, a.col2, b1.cola b1a, b2.cola b2a
from tablea a
inner join tableb b1 on (b1.id = a.id and b1.feature = 24)
inner join tableb b2 on (b2.id = a.id and b2.feature = 25);
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SQLFiddle在这里。