错误:无法将参数从'int [10]'转换为'int'

Question

这是一个用于实现Stack的相当简单的程序.但与的声明一个问题push(),pop()和display()功能.错误陈述如下.请帮我弄清楚问题所在.

错误:

error C2664: 'push' : cannot convert parameter 1 from 'int [10]' to 'int'
error C2664: 'pop' : cannot convert parameter 1 from 'int [10]' to 'int'
error C2664: 'display' : cannot convert parameter 1 from 'int [10]' to 'int'

程序:

#include<iostream>
#define STACKSIZE 10
using namespace std;
void push(int,int,int);
void pop(int,int);
void display(int,int);
int main()
{
    int stack[STACKSIZE],n,data,stackptr=-1;
    while(1)
    {
        cout<<"1. Push\n2. Pop\n3. Display\n4. Exit\n";
        cin>>n;
        switch(n)
        {
        case 1:
            cout<<"\nEnter a data to push: ";
            cin>>data;
            push(stack,stackptr,data);
            break;
        case 2:
            pop(stack, stackptr);
            break;
        case 3:
            display(stack, stackptr);
            break;
        case 4:
            exit(1);
            break;
        default:
                cout<<"\nEnter correct choice...\n\n";
        }
    }
    system("pause");
    return 0;
}
void display(int stack[STACKSIZE], int &stackptr)
{
    cout<<"\n\n";
    for(int i=0;i<stackptr;i++)
        cout<<stack[i]<<"\n";
    cout<<"\n\n";
}
void push(int stack[STACKSIZE],int &stackptr, int data)
{
    if(stackptr == STACKSIZE - 1)
    {
        cout<<"\n\nStack full\n\n";
        return ;
    }
    stackptr++;
    stack[stackptr] = data;
}
void pop(int stack[STACKSIZE], int &stackptr)
{
    if(stackptr == 0)
    {
        cout<<"\n\nStack Empty\n\n";
        return ;
    }
    stackptr = stackptr-1;
}

Answer 1

Gangadhar和Jansel给出的答案是不完整的.您是通过引用传递值,所以这还不够:

void push(int stack[size],int,int);

这就是你需要的:

void push(int[],int&,int);
void pop(int[],int&);
void display(int[],int&);