UIButton具有按住操作和释放操作

Question

我想创建一个可以按下的UIButton,当按下它时会调用"hold down"动作一次.当它被释放时,调用"hold was release"动作.

此代码无法正常工作,因为触摸可以在按钮内移动,并且事件不会按正确的顺序触发

[button handleControlEvent:UIControlEventTouchDown withBlock:^{
        [self performMomentaryAction:PXActionTypeTouchDown];
    }];
[button handleControlEvent:UIControlEventTouchUpInside withBlock:^{
        [self performMomentaryAction:PXActionTypeTouchUp];
    }];

句柄控制事件基于UIBUtton +块实现

Answer 1

试试这个

  UIButton *aButton = [UIButton buttonWithType:UIButtonTypeRoundedRect];
  aButton.frame = CGRectMake(xValue, yValue, 45, 45);
  [aButton addTarget:self action:@selector(holdDown) forControlEvents:UIControlEventTouchDown];
  [aButton addTarget:self action:@selector(holdRelease) forControlEvents:UIControlEventTouchUpInside];


 - (void)holdDown
  {
     NSLog(@"hold Down");
  }

  - (void)holdRelease
  {
      NSLog(@"hold release");

  }

对于NSPratik的情况:你可以使用这个事件UIControlEventTouchUpOutside如果用户长按一下按钮,一段时间后,用户不会松开手指,而是将他/她的手指从按钮的边界移开.再添加一个活动.

  UIButton *aButton = [UIButton buttonWithType:UIButtonTypeRoundedRect];
  aButton.frame = CGRectMake(xValue, yValue, 45, 45);
  [aButton addTarget:self action:@selector(holdDown) forControlEvents:UIControlEventTouchDown];
  [aButton addTarget:self action:@selector(holdRelease) forControlEvents:UIControlEventTouchUpInside];
  [aButton addTarget:self action:@selector(holdReleaseOutSide) forControlEvents:UIControlEventTouchUpOutside]; //add this for your case releasing the finger out side of the button's frame

 //add this method along with other methods 
  - (void)holdReleaseOutSide
  {
     NSLog(@"hold release out side");
  }

Swift版本

 var  aButton:UIButton = UIButton.buttonWithType(UIButtonType.Custom) as UIButton
 aButton.frame = CGRectMake(xValue,yValue, 45, 45)
 aButton.setTitle("aButton", forState: UIControlState.Normal)
 aButton.backgroundColor = UIColor.greenColor()
 aButton.addTarget(self, action: Selector("holdRelease:"), forControlEvents: UIControlEvents.TouchUpInside);
 aButton.addTarget(self, action: Selector("HoldDown:"), forControlEvents: UIControlEvents.TouchDown)
 self.addSubview(aButton)

 //target functions   
 func HoldDown(sender:UIButton)
 {
    print("hold down")
 }

 func holdRelease(sender:UIButton)
 {
    print("hold release")
 }

Answer 2

我自己也遇到过这个问题,大多数情况下我们都会使用这些事件: -

//这个事件运行正常并且开火

[aButton addTarget:self action:@selector(holdDown) forControlEvents:UIControlEventTouchDown];

//这根本不会发射

[aButton addTarget:self action:@selector(holdRelease) forControlEvents:UIControlEventTouchUpInside];

解:-

使用长按手势识别器: -

 UILongPressGestureRecognizer *btn_LongPress_gesture = [[UILongPressGestureRecognizer alloc] initWithTarget:self action:@selector(handleBtnLongPressgesture:)];
[aButton addGestureRecognizer:btn_LongPress_gesture];

手势的实现: -

- (void)handleBtnLongPressgesture:(UILongPressGestureRecognizer *)recognizer{


//as you hold the button this would fire

if (recognizer.state == UIGestureRecognizerStateBegan) {

    [self holdDown];
}

//as you release the button this would fire

if (recognizer.state == UIGestureRecognizerStateEnded) {

    [self holdRelease];
}
}

Answer 3

试试这个

添加TouchDown,Touch Up Inside,Touch Up Outside事件到你的按钮

 -(IBAction)theTouchDown:(id)sender
 {

    timer = [NSTimer scheduledTimerWithTimeInterval:0.2
                                             target:self
                                           selector:@selector(performFunctionality)
                                           userInfo:nil
  }
-(IBAction)theTouchUpInside:(id)sender
{
[timer invalidate];
timer = nil;
[self performFunctionality];

 }


 -(IBAction)theTouchUpOutside:(id)sender
 {
[timer invalidate];
timer = nil;
 }

-(void)performFunctionality
 {
 //write your logic
 }