Gson使用递归依赖关系反序列化复杂对象

Question

我有几个包含彼此递归依赖的类,我使用Gson GraphAdapterBuilder将它们序列化为JSON格式,它完美地运行.现在我想将它们反序列化为相同的结构,但无法找到方法.

我做了一个例子:

class ClassA{
    public int field;
    public ClassB parent;
    public ClassA(int f, ClassB p){
        field = f;
        parent = p;
    }
}

class ClassB{
    public Vector<ClassA> vector = new Vector<ClassA>();
}

...

ClassB b = new ClassB();        

ClassA a1 = new ClassA(1,b);
ClassA a2 = new ClassA(2,b);
ClassA a3 = new ClassA(3,b);

b.vector.add(a1);
b.vector.add(a2);
b.vector.add(a3);

//Serializing object b

GsonBuilder gsonBuilder = new GsonBuilder();

new GraphAdapterBuilder()
    .addType(ClassA.class)
    .addType(ClassB.class)
    .registerOn(gsonBuilder);

Gson gson = gsonBuilder.create();

String json = gson.toJson(b);

输出给了我想要的东西:

{"0x1":{"vector":["0x2","0x3","0x4"]},"0x2":{"field":1,"parent":"0x1"},"0x3":{"field":2,"parent":"0x1"},"0x4":{"field":3,"parent":"0x1"}}

有没有办法将该json字符串反序列化为ClassB的对象？

Answer 1

好的,我找到了解决方案.这很简单.只需使用fromJson而不是toJson函数,使用相同的GraphAdapterBuilder结构.

    ...
    GsonBuilder gsonBuilder = new GsonBuilder();
    new GraphAdapterBuilder()
            .addType(ClassA.class)
            .addType(ClassB.class)
            .registerOn(gsonBuilder);
    gson = gsonBuilder.create();
    ?lassB B = gson.fromJson(json,ClassB.class);

    System.out.println("B " + B.vector);
    for(ClassA classA:B.vector){
        System.out.println(classA.field + "  " + classA.parent);
    }

输出是:

    B [ClassA@10178f2b, ClassA@7ab8584d, ClassA@5cad662c]
    1  ClassB@7c0f023c
    2  ClassB@7c0f023c
    3  ClassB@7c0f023c