尝试/捕获预期'('错误

Question

我正在尝试使用try/catch.我非常确定语法是正确的但不确定为什么我会收到这个错误:'('expect catch ^

这是我的代码:

    Random first_number = new Random();
    Random second_number = new Random();

    int number_1;
    int number_2;

    int answer_M;
    String answer;
    int correctAnswer_M = 0;


    for(int i=1;i<=20;i++)
    {
        try
        {
            number_1 = first_number.nextInt(10);
            number_2 = second_number.nextInt(10);

            System.out.print("\n         " + i + ".) ");
            System.out.print(number_1 + " multiplied by " + number_2 +" = ");
            answer_M = Integer.parseInt(answer);

                if(answer_M==(number_1 * number_2))
                {
                    correctAnswer_M = correctAnswer_M + 1;
                }
        }
        catch
        {
            System.out.print("Please enter an answer.");
            i=i-1;
        }
    }

期待你的回复.谢谢!:)

Answer 1

编译器抱怨(刚刚失踪catch.你需要添加Exception你正在捕捉.-

catch (Exception e)

更多关于catch块的信息.