NEO*_*NEO 3 java collections wildcard
我有一个HashMap<Integer,String>
.我尝试了以下代码来查询Map并返回所有可能的值
public Collection<String> query(String queryStr) {
List<String> list = new ArrayList<String>();
for (Map.Entry<String, Integer> entry : myMap.entrySet()) {
if (queryStr.matches(entry.getKey()))
list.add(entry.getKey());
}
if (list.isEmpty())
return null;
else
return list;
}
Run Code Online (Sandbox Code Playgroud)
如果地图有"test","best","crest","zest","testy","tether","temper","teat","tempest"
.te*t
应该返回的查询"teat","tempest","test"
.对于'test*',它应该返回"test","testy".怎么实现呢?是否有任何通配符搜索字符串?我不能使用任何外部库.
String queryStr="te*t";
queryStr = queryStr.replaceAll("\\*", "\\\\w*");
System.out.println(query(queryStr));
Run Code Online (Sandbox Code Playgroud)
完整的计划
public class sample {
static List<String> values = Arrays.asList("test","best","crest","zest","testy","tether","temper","teat","tempest");
/**
* @param args
*/
public static void main(String[] args) {
String queryStr = "te*t";
queryStr = queryStr.replaceAll("\\*", "\\\\w*");
System.out.println(queryStr);
System.out.println(query(queryStr));
}
public static Collection<String> query(String queryStr) {
List<String> list = new ArrayList<String>();
for (String str : values) {
if (str.matches(queryStr))
list.add(str);
}
if (list.isEmpty())
return null;
else
return list;
}
}
Run Code Online (Sandbox Code Playgroud)