简单的XML反序列化

Bin*_*mas 5 java xml serialization xml-serialization

我正在尝试使用Simple XML序列化程序.我对XML-> Java的反序列化更感兴趣.这是我的代码作为单元测试:

import java.io.StringReader;
import java.io.StringWriter;

import junit.framework.TestCase;

import org.simpleframework.xml.Attribute;
import org.simpleframework.xml.Root;
import org.simpleframework.xml.Serializer;
import org.simpleframework.xml.core.Persister;

public class SimpleTest extends TestCase {
    public void testWriting() throws Exception {
        StringWriter writer = new StringWriter();
        Address address = new Address("1234 Main Street", "San Francisco", "CA");
        Serializer serializer = new Persister();

        serializer.write(address, writer);
        System.out.println("Wrote: " + writer.getBuffer());
    }

    public void testReading() throws Exception {
        String input = "<address street='1234 Main Street' city='San Francisco' state='CA'/>";
        Serializer serializer = new Persister();
        System.out.println("Read back: " + serializer.read(Address.class, new StringReader(input)));
    }
}

@Root
class Address {
    @Attribute(name="street")
    private final String street;

    @Attribute(name="city")
    private final String city;

    @Attribute(name="state")
    private final String state;

    public Address(@Attribute(name="street") String street, @Attribute(name="city") String city, @Attribute(name="state") String state) {
        super();
        this.street = street;
        this.city = city;
        this.state = state;
    }

    @Override
    public String toString() {
        return "Address [city=" + city + ", state=" + state + ", street=" + street + "]";
    }   
}
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这是有效的,但是@AttributeAddress类中的重复注释(在字段和构造函数参数中)看起来很难看.有办法:

  • 从字段名称中简单地找出属性名称?
  • 有简单的忽略序列化,以便我可以摒弃字段或构造函数参数?

DJ.*_*DJ. 1

我认为您不需要所有的重复和额外的注释属性。如果名称与对象属性相同,则默认使用该名称。

所以你可以将其声明为:

@Root
class Address {
    @Attribute
    private final String street;

    @Attribute
    private final String city;

    @Attribute
    private final String state;

    public Address(String street, String city, String state) {
        super();
        this.street = street;
        this.city = city;
       this.state = state;
   }

   @Override
   public String toString() {
      return "Address [city=" + city + ", state=" + state + ", street=" + street + "]";
   }   
}
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