据说使用django-cms时服务器403/404/500错误页面是一项微不足道的任务.按照旧论坛帖子上的说明创建:
from cms.views import details
def custom_404(request):
response = details(request, 'page-not-found')
response.status_code = 404
return response
...
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Urls.py有一些像这样的行:
handler404 = 'error_pages.views.custom_404'
...
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来自traceback django cms找不到404页面:
File "/home/username/.virtualenvs/venv/lib/python2.7/site-packages/cms/views.py", line 22, in _handle_no_page
raise Http404('CMS: Page not found for "%s"' % slug)
Http404: CMS: Page not found for "page-not-found"
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显然在django-cms中添加了slug所需的自定义页面:'page-not-found'.我错过了一些明显的东西吗 在生产服务器上运行debug=False
.运行django-cms 2.4.2(编辑)
也许用硬编码的样式表来提供简单的错误消息会更好吗?
走进无数的墙壁过度思考问题后,我只是使用基本的403/404/500处理程序:
from django.utils.functional import curry
from django.views.defaults import *
handler500 = curry(server_error, template_name='500.html')
handler404 = curry(page_not_found, template_name='404.html')
handler403 = curry(permission_denied, template_name='403.html')
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为每个错误创建模板,并为样式表添加绝对URL.
问题解决了.在这件微不足道的事情上浪费了很多时间.
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