实体框架 - 选择分组依据,选择最大日期

use*_*377 3 entity-framework

我有一个NoteBrief

public int Id { get; set; } 
public string Title { get; set; } 
public DateTime Created { get; set; }
public int ParentNoteId { get; set; }
Run Code Online (Sandbox Code Playgroud)

数据看起来像

1 Title1 03/31/1987 1
2 Title1 03/31/1988 1
3 Title3 01/01/2000 3
4 Title4 01/01/2001 4
5 Title4 01/01/2005 4
Run Code Online (Sandbox Code Playgroud)

我想要做:

SELECT t1.*
FROM Notes AS t1 LEFT JOIN Notes AS t2
ON (t1.ParentNoteId = t2.ParentNoteId AND t1.Created < t2.Created)
WHERE t2.Created IS NULL;
Run Code Online (Sandbox Code Playgroud)

现在我有:

 public IQueryable<NoteBrief> GetNotes()
    {

        return _ctx.Notes.Select(r => new NoteBrief
        {
            Id = r.Id,
            Title = r.Title,
            Created = r.Created,
            ParentNoteId = r.ParentNoteId,
        });

    }
Run Code Online (Sandbox Code Playgroud)

我对此很满意,但实际上并不需要更新的parentNoteId版本,只需要最后创建的那个,以便我可以链接到它.

我读过很多例子,其中一些使用FirstOrDefault,另一些使用max.每次我尝试实现一个例子,它对我不起作用.

use*_*377 9

实体框架创建最新的IQuerable

这最终对我有用:

        return from e in _ctx.Notes
               group e by e.ParentNoteId into g
               select g.OrderByDescending(e => e.Created).FirstOrDefault() into r
               select new NoteBrief
               {
                   Id = r.Id,
                   Title = r.Title,
                   Created = r.Created,
                   ParentNoteId = r.ParentNoteId,
               };
Run Code Online (Sandbox Code Playgroud)

还编辑了我的原始帖子,我正在寻找正确的查询.

谢谢.