N. *_*jay 2 objective-c abaddressbook ios ios7 xcode5
当我使用ABpeoplePickerNavigationController时,当调用下面的委托时,我试图执行以下操作:
- (BOOL)peoplePickerNavigationController:(ABPeoplePickerNavigationController *)peoplePicker shouldContinueAfterSelectingPerson:(ABRecordRef)person property:(ABPropertyID)property identifier:(ABMultiValueIdentifier)identifier
{
if(property == kABPersonPhoneProperty || property == kABPersonEmailProperty)
{
NSString *name = (__bridge NSString *)ABRecordCopyCompositeName(person);
ABMutableMultiValueRef multi = (ABMultiValueRef)ABRecordCopyValue(person, property);
NSString *number = (__bridge NSString*)ABMultiValueCopyValueAtIndex(multi, identifier);
if(![VZMUtils validateEmail:number])
number = [VZMUtils formatIdentificationNumber:number];
number = [number stringByReplacingOccurrencesOfString:@"." withString:@""];
ALog(@"number %@ and name %@",number,name);
[self.popoverDelegate setDataWithName:name andDetail:number];
}
else
{
UIAlertView *alert = [[UIAlertView alloc] initWithTitle:@"Invalid type selected." message:@"Please select either a phone number or email address to add as a recipient" delegate:nil cancelButtonTitle:@"Ok" otherButtonTitles:nil, nil];
[alert show];
}
[self dismissViewControllerAnimated:YES completion:nil];
return NO;
}
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我得到的变量号是.925.3248930,在控制台中它添加了某种".".在空白的位置.我尝试修剪空白仍然是我这样做非常不成功.伙计们,你能帮助我吗?难道我做错了什么?
你可以试试
number = [number stringByReplacingOccurrencesOfString:@"." withString:@""];
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从结果字符串中删除点.
或者如果有任何其他特殊字符的可能性使用下面的代码
NSCharacterSet *onlyAllowedChars = [[NSCharacterSet characterSetWithCharactersInString:@"0123456789"] invertedSet];
number = [[number componentsSeparatedByCharactersInSet:onlyAllowedChars] componentsJoinedByString:@""];
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