ato*_*eki 3 java collections mergesort arraylist quicksort
我有一个自定义类型Position(x,y,z),现在我创建了一个ArrayList<Position>,我想按z的值排序这个数组,从小到大,我该怎么做呢Collections.sort或者还有其他有效的排序方法吗?
当我尝试使用时
public class PositionComparator implements Comparator<Position> {
@Override
public int compare(Position o1, Position o2) {
// TODO Auto-generated method stub
return o1.height().compareTo(o2.height());
}
}
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得到一个错误
Cannot invoke compareTo(double) on the primitive type double
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尝试
Collections.sort(SortList, new Comparator<Position>(){
public int compare(Position p1, Position p2) {
return p1.z- p2.z;
}
});
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Collections.sort
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例如
class User {
String name;
String age;
public User(String name, String age) {
this.name = name;
this.age = age;
}
public String getAge() {
return age;
}
public void setAge(String age) {
this.age = age;
}
public String getName() {
return name;
}
public void setName(String name) {
this.name = name;
}
}
import java.util.Comparator;
public class ComparatorUser implements Comparator {
public int compare(Object arg0, Object arg1) {
User user0 = (User) arg0;
User user1 = (User) arg1;
int flag = user0.getAge().compareTo(user1.getAge());
if (flag == 0) {
return user0.getName().compareTo(user1.getName());
} else {
return flag;
}
}
}
import java.util.ArrayList;
import java.util.Collections;
import java.util.List;
public class SortTest {
public static void main(String[] args) {
List userlist = new ArrayList();
userlist.add(new User("dd", "4"));
userlist.add(new User("aa", "1"));
userlist.add(new User("ee", "5"));
userlist.add(new User("bb", "2"));
userlist.add(new User("ff", "5"));
userlist.add(new User("cc", "3"));
userlist.add(new User("gg", "6"));
ComparatorUser comparator = new ComparatorUser();
Collections.sort(userlist, comparator);
for (int i = 0; i < userlist.size(); i++) {
User user_temp = (User) userlist.get(i);
System.out.println(user_temp.getAge() + "," + user_temp.getName());
}
}
}
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