将Snake Case转换为更低的Camel Case(lowerCamelCase)

Question

my_string在Python 2.7中从snake case()转换为较低的camel case(myString)的好方法是什么？

显而易见的解决方案是通过下划线拆分,将除第一个单词之外的每个单词大写并重新连接在一起.

但是,我很好奇其他更惯用的解决方案或一种方法RegExp来实现这一点(使用一些case修饰符？)

Answer 1

def to_camel_case(snake_str):
    components = snake_str.split('_')
    # We capitalize the first letter of each component except the first one
    # with the 'title' method and join them together.
    return components[0] + ''.join(x.title() for x in components[1:])

例:

In [11]: to_camel_case('snake_case')
Out[11]: 'snakeCase'

Answer 2

另一艘班轮

def to_camel_case(snake_string):
    return snake_string.title().replace("_", "")

Answer 3

这是另一个需要,仅适用于Python 3.5:

def camel(snake_str):
    first, *others = snake_str.split('_')
    return ''.join([first.lower(), *map(str.title, others)])

Answer 4

有点晚了，但几天前我在 /r/python 上发现了这个：

pip install pyhumps

然后你可以这样做：

import humps

humps.camelize('jack_in_the_box')  # jackInTheBox
# or
humps.decamelize('rubyTuesdays')  # ruby_tuesdays
# or
humps.pascalize('red_robin')  # RedRobin

Answer 5

强制性单行:

import string

def to_camel_case(s):
    return s[0].lower() + string.capwords(s, sep='_').replace('_', '')[1:] if s else s

Answer 6

>>> snake_case = "this_is_a_snake_case_string"
>>> l = snake_case.split("_")
>>> print l[0] + "".join(map(str.capitalize, l[1:]))
'thisIsASnakeCaseString'