Google Guava"zip"两个列表

Question

使用Google Guava(Google Commons),有没有办法将两个大小相同的列表合并到一个列表中,新列表包含两个输入列表的复合对象？

例:

public class Person {
    public final String name;
    public final int age;

    public Person(String name, int age) {
        this.name = name;
        this.age = age;
    }

    public String toString() {
        return "(" + name + ", " + age + ")";
    }
}

和

List<String> names = Lists.newArrayList("Alice", "Bob", "Charles");
List<Integer> ages = Lists.newArrayList(42, 27, 31);

List<Person> persons =
    transform with a function that converts (String, Integer) to Person
System.out.println(persons);

输出:

[(Alice, 42), (Bob, 27), (Charles, 31)]

Answer 1

从番石榴21开始,这可以通过以下方式实现Streams.zip():

List<Person> persons = Streams.zip(names.stream(), ages.stream(), Person::new)
                              .collect(Collectors.toList());

Answer 2

看起来这个目前还没有Guava,但是它是一个理想的功能.特别是看到这个github问题Iterators.zip().

Answer 3

假装这是一种番石榴方法:

for (int i = 0; i < names.size(); i++) {
    persons.add(new Person(names.get(i), ages.get(i)));
}