使用EclipseLink和Querydsl的自定义数据类型

Question

我已经创建了一个自定义数据类型来存储有效和规范化的电子邮件地址:

public class Email implements Serializable {

    private final String value;

    public Email(String emailAddress) {
        this.value = normalize(emailAddress);
        if (!isValid(value)) {
            throw new IllegalArgumentException("Email address format is not valid: " + value);
        }
    }
    ...
}

其对应的JPA 2.1转换器用于自动存储和从数据库检索:

@Converter(autoApply = true)
public class EmailConverter implements AttributeConverter<Email, String> {

    @Override
    public String convertToDatabaseColumn(Email email) {
        return email == null ? null : email.toString();
    }

    @Override
    public Email convertToEntityAttribute(String email) {
        return email == null ? null : new Email(email);
    }

}

现在,我可以将它用作人物实体的属性:

public class Person extends BaseEntity {

    private String name;

    private LocalDate birthDate;

    @QueryType(PropertyType.STRING)
    private Email email;

    ...
}

这完美无缺.但是当我尝试通过使用Querydsl开始他们的电子邮件地址找到所有人时,我遇到了问题.我已经使用@QueryTypeString 注释了电子邮件属性.这样,Querydsl元模型就是这样创建的,我能够.startsWith()像这样进行查询(使用):

private static final QPerson person = QPerson.person;

public List<Person> getEmailStartWith(String pattern) {
    pattern = Email.normalize(pattern);
    return new JPAQuery(getEntityManager())
        .from(person)
        .where(person.email.startsWith(pattern))
        .orderBy(person.email.asc())
        .list(person);
}

但是当我运行它时我得到了这个异常:

java.lang.IllegalArgumentException: You have attempted to set a value of type class java.lang.String for parameter 1 with expected type of class xxx.Email from query string select person
from Person person
where person.email like ?1 escape '!'
order by person.email asc.
at org.eclipse.persistence.internal.jpa.QueryImpl.setParameterInternal(QueryImpl.java:932) ~[eclipselink-2.5.0.jar:2.5.0.v20130507-3faac2b]
at org.eclipse.persistence.internal.jpa.QueryImpl.setParameterInternal(QueryImpl.java:906) ~[eclipselink-2.5.0.jar:2.5.0.v20130507-3faac2b]
at org.eclipse.persistence.internal.jpa.EJBQueryImpl.setParameter(EJBQueryImpl.java:469) ~[eclipselink-2.5.0.jar:2.5.0.v20130507-3faac2b]
at org.eclipse.persistence.internal.jpa.EJBQueryImpl.setParameter(EJBQueryImpl.java:1) ~[eclipselink-2.5.0.jar:2.5.0.v20130507-3faac2b]
at com.mysema.query.jpa.impl.JPAUtil.setConstants(JPAUtil.java:44) ~[querydsl-jpa-3.2.1.jar:na]
at com.mysema.query.jpa.impl.AbstractJPAQuery.createQuery(AbstractJPAQuery.java:130) ~[querydsl-jpa-3.2.1.jar:na]
at com.mysema.query.jpa.impl.AbstractJPAQuery.createQuery(AbstractJPAQuery.java:97) ~[querydsl-jpa-3.2.1.jar:na]
at com.mysema.query.jpa.impl.AbstractJPAQuery.list(AbstractJPAQuery.java:240) ~[querydsl-jpa-3.2.1.jar:na]
...

我可以使用JPQL获得正确的结果(以及一个不优雅的技巧concat):

public List<Person> getEmailStartWith(String pattern) {
    pattern = Email.normalize(pattern);
    return getEntityManager()
        .createQuery("select p from Person p where p.email like concat(?1, '%')", Person.class)
        .setParameter(1, pattern)
        .getResultList();
}

但我当然更喜欢Querydsl的类型安全.可以使用此库创建此查询吗？

Answer 1

根据Querydsl创建者Timo Westk\xc3\xa4mper的说法，这个问题与EclipseLink更相关。

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