如何将其转换为使用JOINS?
SELECT j.job_id, j.name AS job_name, a.name AS advertiser_name, j.time_added, j.active, j.moderated
FROM jobs j, advertisers a
WHERE a.advertiser_id = j.advertiser_id
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您可以使用以下联接来编写:
SELECT *
FROM jobs j
JOIN advertisers a
ON a.advertiser_id = j.advertiser_id
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