我试图使用wordpress从其他数据库访问自定义帖子.为此,我更改了当前的$wpdb全局变量:
$wpdb = new wpdb( $user, $pass, $db, $host );
$wpdb->show_errors();
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这没有显示任何错误,但是当我尝试使用时WP_Query:
$args = array('post_type'=>'produtos');
$newloop = new WP_Query($args);
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我收到以下错误:
WordPress数据库错误:[您的SQL语法有错误; 查看与您的MySQL服务器版本对应的手册,以便在'FROM WHERE 1 = 1 AND .post_type ='produtos'AND(.post_status ='发布'或.'在第1行)附近使用正确的语法
SELECT SQL_CALC_FOUND_ROWS .ID FROM WHERE 1 = 1 AND .post_type ='produtos'AND(.post_status ='publish'OR .post_author = 1 AND .post_status ='private')ORDER BY .post_date DESC LIMIT 0,10
如果我使用$wpdb->get_results()和$wpdb->get_var()功能,我可以实现我想要的:
$wpdb = new wpdb( $user, $pass, $db, $host );
$rows = $wpdb->get_results("SELECT * FROM wp_posts where post_type='produtos' AND post_status='publish'");
foreach ($rows as $produto) {
$id = $produto->ID;
$title = $produto->post_title;
$valor = $wpdb->get_var("SELECT meta_value FROM wp_postmeta WHERE meta_key = 'preco' AND post_id = $id");
$url_id = $wpdb->get_var("SELECT meta_value from wp_postmeta where post_id = $id AND meta_key='_thumbnail_id'");
}
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我正在寻找一个优雅的解决方案来解决这个问题.
$wpdb = new wpdb( $user, $pass, $db, $host );
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在创建wpdb对象之后,需要设置表名,它通过调用set_prefix() method它来设置表名.
set_prefix( $prefix, $set_table_names = true )
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如果你检查你的SQL错误.表名是空的.默认表前缀是 'wp_'.
解:
$wpdb = new wpdb( $user, $pass, $db, $host );
$wpdb->set_prefix('wp_');
//then rest of your code..
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