MySQL - 在CASE中组合多个WHEN条件

Question

我正在尝试使用下面的CASE子句将2行结果合并为1.'<26'应该只出现一次,结果应该合并.

SELECT  
    CASE org.size
        WHEN 0 THEN '<26'
        WHEN 1 THEN '<26'
        WHEN 2 THEN '26-50'
        WHEN 3 THEN '51-100'
        WHEN 4 THEN '101-250'
        WHEN 5 THEN '251-500'
        WHEN 6 THEN '501-1000'
        WHEN 7 THEN '1001-5000'
        ELSE '5000+' END
        AS 'Size',
        COUNT(DISTINCT org.id) AS '# of Companies'
FROM org INNER JOIN usr ON usr.orgid = org.id
    INNER JOIN usr_role ON usr.id = usr_role.usrid
WHERE org.deleted = 0 AND usr.brnd = 1 AND usr_role.role = 1
GROUP BY org.size;

Answer 1

这个怎么样？

SELECT  CASE 
          WHEN org.size IN (0, 1) THEN '<26'
          WHEN org.size = 2 THEN '26-50'
          WHEN org.size = 3 THEN '51-100'
          WHEN org.size = 4 THEN '101-250'
          WHEN org.size = 5 THEN '251-500'
          WHEN org.size = 6 THEN '501-1000'
          WHEN org.size = 7 THEN '1001-5000'
        ELSE '5000+' END AS Size, ....

问题是,你是分组记录org.size造成<26在两个不同的群体,因为他们原本0和1.

这会工作,

GROUP BY CASE 
          WHEN org.size IN (0, 1) THEN '<26'
          WHEN org.size = 2 THEN '26-50'
          WHEN org.size = 3 THEN '51-100'
          WHEN org.size = 4 THEN '101-250'
          WHEN org.size = 5 THEN '251-500'
          WHEN org.size = 6 THEN '501-1000'
          WHEN org.size = 7 THEN '1001-5000'
        ELSE '5000+' END