GUI(输入和输出矩阵)?

Ser*_*gey -2 python user-interface tkinter pyqt4

Python 3.3.2 Hello.My问题 - 需要为输入数据(矩阵或表)创建GUI.并从此表单数据中获取.例如:

float

完美的解决方案是输入形式的限制(只有浮动).

问题:我能用什么?Tkinter没有表.. wxPython不支持Python 3. PyQt4?(mb你有例子如何从tabel中获取数据A=[[1.02,-0.25,-0.30,0.515],[-0.41,1.13,-0.15,1.555],[-0.25,-0.14,1.21,2.780]]?)
任何人都有想法?

Bry*_*ley 10

使用tkinter,您不需要特殊的表小部件来执行此操作 - 只需创建正常条目小部件的网格.如果你有这么多,你需要一个滚动条,它稍微有点困难(这个网站上有一些例子可以做到这一点),但只是为了创建一个小的网格,它非常简单.

这是一个包含一些输入验证的示例:

import tkinter as tk

class SimpleTableInput(tk.Frame):
    def __init__(self, parent, rows, columns):
        tk.Frame.__init__(self, parent)

        self._entry = {}
        self.rows = rows
        self.columns = columns

        # register a command to use for validation
        vcmd = (self.register(self._validate), "%P")

        # create the table of widgets
        for row in range(self.rows):
            for column in range(self.columns):
                index = (row, column)
                e = tk.Entry(self, validate="key", validatecommand=vcmd)
                e.grid(row=row, column=column, stick="nsew")
                self._entry[index] = e
        # adjust column weights so they all expand equally
        for column in range(self.columns):
            self.grid_columnconfigure(column, weight=1)
        # designate a final, empty row to fill up any extra space
        self.grid_rowconfigure(rows, weight=1)

    def get(self):
        '''Return a list of lists, containing the data in the table'''
        result = []
        for row in range(self.rows):
            current_row = []
            for column in range(self.columns):
                index = (row, column)
                current_row.append(self._entry[index].get())
            result.append(current_row)
        return result

    def _validate(self, P):
        '''Perform input validation. 

        Allow only an empty value, or a value that can be converted to a float
        '''
        if P.strip() == "":
            return True

        try:
            f = float(P)
        except ValueError:
            self.bell()
            return False
        return True

class Example(tk.Frame):
    def __init__(self, parent):
        tk.Frame.__init__(self, parent)
        self.table = SimpleTableInput(self, 3, 4)
        self.submit = tk.Button(self, text="Submit", command=self.on_submit)
        self.table.pack(side="top", fill="both", expand=True)
        self.submit.pack(side="bottom")

    def on_submit(self):
        print(self.table.get())


root = tk.Tk()
Example(root).pack(side="top", fill="both", expand=True)
root.mainloop()
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有关输入验证的更多信息,请参见此处:交互式验证tkinter中的Entry小部件内容