获取LinearLayout由Id使用Xamarin返回null

Question

我为什么要这样mainLayout==null？

protected override void OnCreate (Bundle bundle)
{
    base.OnCreate (bundle);
    SetContentView (Resource.Layout.Main);
    LinearLayout mainLayout = FindViewById<LinearLayout> (Resource.Layout.Main);//return null
    mainLayout.Touch+=(s,e)=>
    {
         //something
    }
}

如何获取MainLayout或如何添加事件处理程序Touch？

Resource.designer.cs:

public partial class Layout
{
    public const int Main = 2130903041;
    //other
}

Answer 1

LinearLayout mainLayout = FindViewById<LinearLayout> 
                                   (Resource.Layout.Main);//return null

您正在使用布局文件作为参数: Resource.Layout.Main

你应该使用的是id你在里面分配给你的LinearLayout Resource.Layout.Main.

尝试:

LinearLayout mainLayout = FindViewById<LinearLayout> 
                                   (Resource.Id.linear_layout_id);

Answer 2

在XML上设置一个ID(android:id ="@ + id/mainLayoutID"),其中包含名为"mainLayout"的LinearLayout.

然后:

@Override
protected void onCreate(final Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.activity_main);

    // Your layout reference
    final LinearLayout mainLayout = (LinearLayout) findViewById(R.id.mainLayoutID);

}