Shell表单不验证JSFiddle

use*_*835 15 javascript forms

当我运行这个JSFiddle时,我得到了这个冗长的错误:http://jsfiddle.net/YqENs/

{"error": "Shell form does not validate{'html_initial_name': u'initial-js_lib', 'form': <mooshell.forms.ShellForm object at 0xa965bac>, 'html_name': 'js_lib', 'html_initial_id': u'initial-id_js_lib', 'label': u'Js lib', 'field': <django.forms.models.ModelChoiceField object at 0xaaeb76c>, 'help_text': '', 'name': 'js_lib'}{'html_initial_name': u'initial-js_wrap', 'form': <mooshell.forms.ShellForm object at 0xa965bac>, 'html_name': 'js_wrap', 'html_initial_id': u'initial-id_js_wrap', 'label': u'Js wrap', 'field': <django.forms.fields.TypedChoiceField object at 0xa9f82cc>, 'help_text': '', 'name': 'js_wrap'}"}
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这是代码(w/html):

<!DOCTYPE html>
<html>
<head>
<script>
function greeting()
{
document.getElementById("p1").innerHTML=document.forms["frm1"]["fname"].value;
}
</script>
</head>

<body>

What is your name?<br>
<form name="frm1" onsubmit="greeting()" method="post">
<input type="text" name="fname">
<input type="submit" value="Submit">
</form>

<p id="p1"></p>

</body>
</html>
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Spa*_*Dog 10

我想问题是来自提交,我不认为你真的想在那里加载新页面,所以尝试:onsubmit="greeting(); return false;"调用你的函数但停止表单提交事件.

否则提交操作将尝试重新加载页面 - jsFiddle不太喜欢.